I believe you will get .5 TB in this example, no?
A.
--
Adam Sherman
+1.613.797.6819
On 2009-08-12, at 16:44, Erik Trimble <erik.trim...@sun.com> wrote:
Eric D. Mudama wrote:
On Wed, Aug 12 at 12:11, Erik Trimble wrote:
Anyways, if I have a bunch of different size disks (1.5 TB, 1.0 TB,
500 GB, etc), can I put them all into one big array and have data
redundancy, etc? (RAID-Z?)
Yes. RAID-Z requires a minimum of 3 drives, and it can use
different drives. Depending on the size differences, it will do the
underlying layout in different ways. Depending on the number and
size of the disks, ZFS is likely the best bet for using the most
total space.
I don't believe this is correct, as far as I understand it, RAID-Z
will use the lowest-common-denominator for sizing the overall array.
You'll get parity across all three drives, but it won't alter parity
schemes for different regions of the disks.
Yes, if you stick (say) a 1.5TB, 1TB, and .5TB drive together in a
RAIDZ, you will get only 1TB of usable space. Of course, there is
always the ability to use partitions instead of the whole disk, but
I'm not going to go into that. Suffice to say, RAIDZ (and
practically all other RAID controllers, and volume managers) don't
easily deal maximizing space with different size disks.
--
Erik Trimble
Java System Support
Mailstop: usca22-123
Phone: x17195
Santa Clara, CA
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