“I drink your milkshake.” >From the movie There Will Be Bandwidth.
From: John Blake Sent: Thursday, August 11, 2016 3:24 PM To: af@afmug.com Subject: Re: [AFMUG] B11 But that B in Shannon's Theorem keeps getting big. That 10Gbps radio uses 2Ghz channels. That results in a lot of C On Thu, Aug 11, 2016 at 9:02 AM, Ken Hohhof <af...@kwisp.com> wrote: There are bumper stickers “Obey Gravity ... It’s the Law”. Maybe you need to sell Shannon’s Law bumper stickers. Ooops, it’s Shannon’s THEOREM. So you can be a Shannon denier. From: Chuck McCown Sent: Thursday, August 11, 2016 9:36 AM To: af@afmug.com Subject: Re: [AFMUG] B11 When they figure a way around this let me know: C=B Log2 ((1+S/N) (Shannon/Hartley) From: Kurt Fankhauser Sent: Wednesday, August 10, 2016 8:24 PM To: af@afmug.com Subject: Re: [AFMUG] B11 wow 10Gbps over wireless? Give it a couple years and there will be an 80ghz Airfiber doing these speeds.... I can't wait. On Wed, Aug 10, 2016 at 3:10 PM, John Blake <jbl...@n1networks.com> wrote: All in for a Huawei RTN-380 including brackets, antennas, software, licensing, cables, accessories, etc. comes out between about $22k-30k per link depending on which options you pick. Also, if 4Gbps isn't good enough, there is the RTN-380H that does 10G wireless. The specs on this are insane. a.. 10Gbps throughput b.. 2000 Mhz channel spacing, 128QAM modulation c.. SFP+ interfaces On Wed, Aug 10, 2016 at 11:00 AM, Joe Novak <jno...@lrcomm.com> wrote: I'm talking 706 FT, give or take 6 inches On Wed, Aug 10, 2016 at 11:52 AM, Eric Kuhnke <eric.kuh...@gmail.com> wrote: Depends on your distance, if you're going 1 km vs. 2.5 to 4 km.... It is definitely a VERY narrow beam width. Particularly with 60cm antennas. I wouldn't do it on anything that sways. On Wed, Aug 10, 2016 at 6:07 AM, Joe Novak <jno...@lrcomm.com> wrote: How stable of a structure do you need for 70/80Ghz? Self standing rohn 45 @ 55 ft too much? It's bracketed at 25ft. On Wed, Aug 10, 2016 at 7:02 AM, Kurt Fankhauser <lists.wavel...@gmail.com> wrote: What price range is a Huawei link in? On Wed, Aug 10, 2016 at 2:47 AM, Eric Kuhnke <eric.kuh...@gmail.com> wrote: You cannot directly compare 11 to 80 GHz. Totally different market. I can't do beyond 2.5 km at real five to six nines uptime with 80 GHz (even with +18 Tx power radios). I can do 60 km with 11 if the link will tolerate some ACM. On Aug 9, 2016 9:31 PM, "John Blake" <jbl...@n1networks.com> wrote: It's obviously pricier than the B11, but if you want true symmetrical and a ton of throughput, you could look at the Huawei RTN-380 radios. These will do 4Gbps (2Gbps symmetrical) at full licensing, or there are 1, 2, 3Gbps licensing options. They use 71-76 GHz and 81-86 GHz and so are super easy and cheap to get (lightly) licensed. These are very popular with carriers outside the US, but not so much in the US because of all the Huawei/Ciscolobby disputes, but that has largely been resolved and they have been getting traction here. Let me know if you want more info, we are Huawei VAR. John On Wed, Aug 3, 2016 at 9:54 PM, <mbl...@bamicrowave.com> wrote: Gino, That seems to be the only configuration that meets the requirement. The way I see it, in a traditional FDD system you would license an XPIC pair of frequencies, say 11075 H/V at point A and 11565 H/V at point B. Assuming an 820 running 256QAM you might get 500mbps per polarity per direction, for a two-way aggregate of 2gpbs. You would have licensed 160MHz at each end of the system, for a system efficiency of 2gbps/320MHz = 6 b/s/hz. If you operate a B11 on the same pair of frequencies, you have to use their FD mode which a typical PCN claims will deliver 736mbps. It would seem that this can be viewed as a two-way aggregate rate, because the radios still take turns transmitting as in a true TDMA system. So, the system efficiency here is 736mbps/320MHz = 2.3 b/s/hz -- below the requirement of 3 b/s/hz. If you switch the B11 to the normal TDMA mode you will need to transmit on the same frequency from each end of the link. So, in addition to licensing 11075 H and V transmitting from point A, you also need to license 11075 H and V transmitting from point B, which adds another 160MHz at each end. The PCNs show this configuration giving 1.47gbps (again assumed to be an aggregate figure due to the TDMA mode). This is an efficiency of 1.47gbps/640MHz = 2.3 b/s/hz again. However, because you have licensed two frequency pairs, each site can also transmit and receive on the unused 11565 H and V frequencies. If you do this then you get 2*1.47gbps/640MHz = 4.6 b/s/hz. This seems to be the only valid configuration, but does this take two radios at each end, or just one? Mike Black Black & Associates 727-773-9016 ---------------------------- Original Message ---------------------------- Subject: Re: [AFMUG] B11 From: "Gino Villarini" <ginovi...@gmail.com> Date: Wed, August 3, 2016 3:38 pm To: "Animal Farm" <af@afmug.com> -------------------------------------------------------------------------- > but the radio tx in both channels in the both polarites in both ends ... > > On Wed, Aug 3, 2016 at 1:31 PM, Eric Kuhnke <eric.kuh...@gmail.com> wrote: > >> No, it is just as spectrally efficient as any 256QAM radio... One 80 MHz >> "low" channel in both polarities and one 80 MHz "high" channel in both >> polarities, as a typical FDD band plan such as you would use with a >> configuration with 2 dishes, 2 orthomode transducers and 4 radio heads >> (each radio operating in a single polarity) in a 2+0 configuration. >> >> You're arriving at the figure of 320 MHz by counting everything twice. >> >> On Wed, Aug 3, 2016 at 10:28 AM, <mbl...@bamicrowave.com> wrote: >> >>> We haven't had the pleasure of coordinating a B11 link yet, but they >>> certainly seem to be popular based upon the number of PCNs we are >>> seeing. So, a dumb question hopefully based upon a simple misunderstanding >>> of the numbers: I don't see how this meets the FCC minimum efficiency >>> standards for wide channels at 11GHz: >>> >>> 80MHz channels x H and V = 160MHz, but with high/low pairing you double >>> this? to 320MHz occupied per end? So, to meet the 3 b/s/hz requirement at >>> 11GHz your symmetrical throughput would need to be >= 960mbps. What am I >>> missing? >>> >>> Mike Black >>> >>> Black & Associates >>> >>> 727-773-9016 >>> >>> >>> ---------------------------- Original Message ---------------------------- >>> Subject: Re: [AFMUG] B11 >>> From: "Jaime Fink" <ja...@mimosa.co> >>> Date: Tue, August 2, 2016 4:49 pm >>> To: "SmarterBroadband" <li...@smarterbroadband.com> >>> "af@afmug.com" <af@afmug.com> >>> -------------------------------------------------------------------------- >>> >>> > The PHY is 1733 Mbps aggregate, so depending on the chosen window >>> sizes, the top real world TCP speeds we’ve seen are between 1200-1300 Mbps >>> aggregate (75/25 or 50/50 mode), or 600-650 Mbps symmetric (50/50). >>> > >>> > For 11 GHz this assumes high/low pairing of 80 MHz and both >>> polarizations coordinated. >>> > >>> > Jaime Fink • Mimosa<http://www.mimosa.co> • CPO & Co-Founder >>> > >>> > >>> > On August 2, 2016 at 1:34:31 PM, SmarterBroadband ( >>> li...@smarterbroadband.com<mailto:li...@smarterbroadband.com>) wrote: >>> > Can the B11 do 1Gbps Symmetrical? >>> > If not what is best Symmetrical? >>> > Thanks >>> > >>> > >>> > >>> >> >> >