Hi. No. The radius that I talking about is the radius of the circumference, is the only thing that I know in the original picture, I don´t know the angle theta, I don´t know the intersecting points between lines and circumference. I know that I need to find theta to calculate the arc length but I don´t know how to find it. I tried to build triangles and trigonometric formulas but I would not have been able to achieve. bye.
On Jan 5, 2008 1:01 PM, drugz' <[EMAIL PROTECTED]> wrote: > > > Which ratio are talking about ? > > Do you mean, ratio of Arc length with Circumference? > > > > On Jan 5, 8:29pm, "Daniel Bastidas" <[EMAIL PROTECTED]> wrote: > > Hi. > > > > Sorry for my poor english, maybe I don´t explain me well. > > Ok, if A is the area of the circumference then: > > *A = PI*r^2* and *r* = radius of the circumference as shown in figure > > So a mathematic expression for the radius will be: > > *r = (A/PI)^1/2* > > > > If C is the circumference, *C = **2 * PI * r* then > > *r = C/2*PI > > > > *Now I hope that I explained well. > > Don´t worry if you can answer to me, thanks for try. > > bye. > > > > On Jan 5, 2008 9:38 AM, chandra kumar <[EMAIL PROTECTED]> > wrote: > > > > > > > > > Hi, > > > By ratio of circumference, I assume L / C (i.e. the ratio of L:C) > > > > > You mentioned that you know that ratio i.e., you know L / C = k, > > > where k is the ratio of L to C > > > > > which implies L = k * C > > > > > Then by the circumference formula > > > C = 2 * PI * r > > > L = k * 2 * PI * r > > > > > By any chance do you mean ratio to be the ratio of radius and > > > circumference, cause it is always known to 1 / ( 2*PI ) > > > > > Can you write the ratio in a mathematical expression so that I will > also > > > understand. But I'm not sure if I can answer that. > > > > > Thanks and Regards, > > > K.V.Chandra Kumar > > > > > On 05/01/2008, Daniel Bastidas <[EMAIL PROTECTED]> wrote: > > > > > > ups.. sorry > > > > When I said radio I wanted to said ratio or radius of circumference. > for > > > > clarify. > > > > > > > > circumference.JPG > > 6KViewDownload- Hide quoted text - > > > > - Show quoted text - > > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Algorithm Geeks" group. To post to this group, send email to algogeeks@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/algogeeks -~----------~----~----~----~------~----~------~--~---
