i thing that if u negate any value by ! the result will be always a int..
so !a will be a integer value and !a+b due to typecast will be also int..
you can verified this fact by seeing the result of
sizeof (!a+a) => 12
sizeof (!b) =>4
sizeof (!a) =>4
sizeof(!(a+b)) =>4
sizeof (!(!a)) =>4
*- - - - -
WITH REGARDS,
*
*
PRAMENDRA RATHI
*
**
*B.TECH 2ND YEAR*
*COMPUTER SCIENCE AND ENGINEERING*
*NIT ALLAHABAD*
On Thu, Jun 23, 2011 at 5:52 PM, Anika Jain <anika.jai...@gmail.com> wrote:
> int main()
> {
> long double a;
> signed char b;
> printf("%d\n",sizeof(!a+b));
> return 0;
> }
>
> why is it 4?? shouldnt it be 12 as per sizeof long double in gccc
>
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