It is because of the ! operator in front of a , !a is always 0(in case a is
value other than 0) so it takes it as integer and hence the size is 4 bytes
whereas only a you will get 12 . The ! changes the data type here .
Hope it clears the doubt :)
-----------------------------------------
Rajeev N B
I Blog @ www.opensourcemania.co.cc
On Thu, Jun 23, 2011 at 5:52 PM, Anika Jain <anika.jai...@gmail.com> wrote:
> int main()
> {
> long double a;
> signed char b;
> printf("%d\n",sizeof(!a+b));
> return 0;
> }
>
> why is it 4?? shouldnt it be 12 as per sizeof long double in gccc
>
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