ya i got it.. thanx
On Thu, Jun 23, 2011 at 6:01 PM, rajeev bharshetty <rajeevr...@gmail.com>wrote:
> It is because of the ! operator in front of a , !a is always 0(in case a is
> value other than 0) so it takes it as integer and hence the size is 4 bytes
> whereas only a you will get 12 . The ! changes the data type here .
> Hope it clears the doubt :)
>
>
> -----------------------------------------
>
>
> Rajeev N B
>
> I Blog @ www.opensourcemania.co.cc
>
> On Thu, Jun 23, 2011 at 5:52 PM, Anika Jain <anika.jai...@gmail.com>wrote:
>
>> int main()
>> {
>> long double a;
>> signed char b;
>> printf("%d\n",sizeof(!a+b));
>> return 0;
>> }
>>
>> why is it 4?? shouldnt it be 12 as per sizeof long double in gccc
>>
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