On Thu, Jan 5, 2012 at 12:44 PM, Kostya Vasilyev <kmans...@gmail.com> wrote:
> Ok, great.
>
> One simple thing you can do is to check the item's position, e.g. set odd
> items to blue and even items to red (just to pick an example).
The only logic which knows the desired color is the main view which
populated the list view. It seems that android can not do what I
desire.
>
> Beyond that, consider creating a proper "data item" class.
>
> The adapter's getView would then examine the data item at the requested
> position and make the decision on how to present it, based on its field
> values (e.g. names starting with "A" are red, starting with "B" are green,
> the rest are blue).
>
> Also consider extending BaseAdapter rather than ArrayAdapter - it's just a
> little bit more work, but should really clarify things for you.
>
> The links posted by TreKing are Mark are good.
>
> -- Kostya
>
> 5 января 2012 г. 21:31 пользователь John Davis <davi...@gmail.com> написал:
>
>> Kostya,
>>
>> Tip of the hat to you. That worked. It will set all the items to
>> blue text. I appreciate your help a lot.
>>
>> Now, is there a simple way to do this selectively? I saw you could
>> tag items and then look based upon a tag. Perhaps that will work? I
>> would prefer that the class which creates the array adapter and list
>> view set the tag for the color and the array adapter to draw the line
>> items in blue or red based upon this tag.
>>
>> John
>>
>> On Thu, Jan 5, 2012 at 12:13 PM, Kostya Vasilyev <kmans...@gmail.com>
>> wrote:
>> > Aha!
>> >
>> > android.R.layout.simple_list_item_1 is defined in the platform, you can
>> > find
>> > it under <your Android sdk
>> > directory>/platforms/platform-<version>/data/res/layout (that data/res
>> > is
>> > very useful to look up things):
>> >
>> > The whole layout is a TextView, and its id is "@android:id/text1",
>> > which, on
>> > the Java side of things, is android.R.id.text1.
>> >
>> > So you'd do something like.
>> >
>> > @Override
>> > public View getView(int position, View convertView, ViewGroup
>> > parent)
>> > {
>> > View row = super.getView(position, convertView, parent);
>> > TextView text = (TextView)
>> > row.findViewById(android.R.id.text1);
>> > text.setTextColor(0x64788e);
>> > return row;
>> > }
>> >
>> > Or just this, knowing that the layout is just one TextView:
>> >
>> > TextView text = (TextView) row;
>> >
>> > The direct typecast should work for the hello-listview sample, as that
>> > also
>> > uses a row layout containing a single TextView with no children (and no
>> > id,
>> > so findViewById won't work here).
>> >
>> > -- Kostya
>> >
>> > 5 января 2012 г. 21:04 пользователь John Davis <davi...@gmail.com>
>> > написал:
>> >
>> >> Hello
>> >>
>> >> On Thu, Jan 5, 2012 at 11:53 AM, Kostya Vasilyev <kmans...@gmail.com>
>> >> wrote:
>> >> > Just to clarify 2:
>> >> >
>> >> > I meant calling super.getView from your adapter's getView, assuming
>> >> > it's
>> >> > a
>> >> > subclass of ArrayAdapter.
>> >> >
>> >> > Do not call adapter.getView from outside the adapter's code, that's
>> >> > meaningless.
>> >>
>> >> That makes sense. Thanks.
>> >>
>> >> >
>> >> > Now the view ids.... What layout id do you use to initialize the
>> >> > adapter?
>> >> > Perhaps android.R.layout.<something>?
>> >>
>> >> I did :
>> >> MyAdapter<String> adapter = new
>> >> MyAdapter<String>(this,android.R.layout.simple_list_item_1, values);
>> >>
>> >> >
>> >> > A side note: my suggestions here are just to patch up things based on
>> >> > the
>> >> > route you've already headed down (using ArrayAdapter).
>> >>
>> >>
>> >> For what it is worth, I can do this:
>> >> public View getView(int position, View convertView, ViewGroup
>> >> parent) {
>> >> TextView text = new TextView(getContext());
>> >> text.setText("Hi, I am position " + position);
>> >> text.setTextColor(Color.parseColor("#64788e"));
>> >> return text;
>> >> }
>> >> That will set the text color to blue, but it will also change the text
>> >> I put in the list.
>> >>
>> >> >
>> >> > One day, as your knowledge grows, you'll want to throw away the
>> >> > three-wheeled bicycle (ArrayAdapter) and create your own, perhaps by
>> >> > extending BaseAdapter.
>> >> >
>> >>
>> >>
>> >> Is this example
>> >>
>> >> http://developer.android.com/resources/tutorials/views/hello-listview.html
>> >> impossible to manipulate the color of individual list items? Or, is
>> >> there a way to patch up this code to do what I want? It seems pretty
>> >> trivial to do. I don't understand why the hooks do not exist for what
>> >> i want to do.
>> >> > -- Kostya
>> >> >
>> >> > 5 января 2012 г. 20:47 пользователь John Davis <davi...@gmail.com>
>> >> > написал:
>> >> >
>> >> >> Hello Kostya,
>> >> >>
>> >> >> Thanks for the reply.
>> >> >>
>> >> >> On Thu, Jan 5, 2012 at 11:39 AM, Kostya Vasilyev
>> >> >> <kmans...@gmail.com>
>> >> >> wrote:
>> >> >> >
>> >> >> > 2:
>> >> >> >
>> >> >> > Yes, you're supposed to call the base class in your case, the
>> >> >> > ArrayAdapter
>> >> >> > will be doing most of the work for you, inflating new or reusing
>> >> >> > existing
>> >> >> > row layouts.
>> >> >>
>> >> >> Ok. I think I am doing what you say.
>> >> >>
>> >> >> >
>> >> >> > 3:
>> >> >> >
>> >> >> > Use view ids that are relevant to (used inside) your actual row
>> >> >> > item
>> >> >> > layout.
>> >> >> >
>> >> >> > I very much doubt that R.id.listView1 is it.
>> >> >>
>> >> >> The listview is created using that id. I did not create any
>> >> >> resources
>> >> >> for the individual items. I don't know how to do that. The example
>> >> >> code I used simply created a listview in xml.
>> >> >>
>> >> >> >
>> >> >> > 4:
>> >> >> >
>> >> >> > view.findViewById() is the getChild call you're looking for, using
>> >> >> > an
>> >> >> > id
>> >> >> > to
>> >> >> > locate the view. Use correct id value and it should work.
>> >> >>
>> >> >> Super. I am glad you confimed I need ot do that. However, as I
>> >> >> said,
>> >> >> I don't know what would be the id of the row items since they are
>> >> >> not
>> >> >> defined.
>> >> >>
>> >> >> >
>> >> >> > -- Kostya
>> >> >> >
>> >> >> > 5 января 2012 г. 20:31 пользователь John Davis <davi...@gmail.com>
>> >> >> > написал:
>> >> >> >>
>> >> >> >> Hello
>> >> >> >>
>> >> >> >> The getView() call for arrayadapter is blank. Is there a
>> >> >> >> document
>> >> >> >> which describes how it works?
>> >> >> >>
>> >> >> >> I have overridden it in order to change the text color of items
>> >> >> >> in a
>> >> >> >> list view. So far, I can't find any code which works.
>> >> >> >>
>> >> >> >> I've tried this:
>> >> >> >>
>> >> >> >> public class MyAdapter<T> extends ArrayAdapter<T> {
>> >> >> >>
>> >> >> >> public MyAdapter(Context context, int textViewResourceId,
>> >> >> >> T[]
>> >> >> >> objects) {
>> >> >> >> super(context, textViewResourceId, objects);
>> >> >> >> }
>> >> >> >> // context, int, <T>[]
>> >> >> >>
>> >> >> >> @Override
>> >> >> >> public View getView(int position, View convertView,
>> >> >> >> ViewGroup
>> >> >> >> parent) {
>> >> >> >> // TODO Auto-generated method stub
>> >> >> >> View row;
>> >> >> >> row = super.getView(position, convertView, parent);
>> >> >> >> TextView text;
>> >> >> >> text = (TextView) row.findViewById(R.id.listView1);
>> >> >> >> text.setTextColor(0x64788e);
>> >> >> >> return row;
>> >> >> >> }
>> >> >> >> }
>> >> >> >>
>> >> >> >>
>> >> >> >> I don't know if I am supposed to call getView in the main code or
>> >> >> >> not,
>> >> >> >> but this will most certain crash the app.
>> >> >> >> The super.getView call seems to get a row in the list. It seems
>> >> >> >> that
>> >> >> >> you then need to get the view associated with that row. I have
>> >> >> >> no
>> >> >> >> idea how to do that. I don't have resource id's for the
>> >> >> >> individual
>> >> >> >> row
>> >> >> >> items. Here, I tried to use the resource id of the list itself.
>> >> >> >> There is not a View.getChild() like call.
>> >> >> >> --
>> >> >> >> John F. Davis
>> >> >> >>
>> >> >> >> 独树一帜
>> >> >> >>
>> >> >> >> --
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>> >> >> >
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>> >> >>
>> >> >>
>> >> >> --
>> >> >> John F. Davis
>> >> >>
>> >> >> 独树一帜
>> >> >>
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>> >>
>> >>
>> >> --
>> >> John F. Davis
>> >>
>> >> 独树一帜
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>>
>> --
>> John F. Davis
>>
>> 独树一帜
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