Re: DT in BGT
UPDATE: Adding 180 degrees and recalculating theta mirrors the angle correctly:
B.pos.z = 50;
deg += 180;
//recalculate theta.
DTR(deg);
B.moving = true;
move();
And the previous movement is mirrored. One thing I do notice that quite frankly royally pisses me off is that when mirroring, the ball doesn't land where it started. In other words, ball starts at position 0, 0, 50. After travelling at 45 degrees, it lands at 31.0134830474854, 31.0134830474854, 0. After mirroring, which should bring it right back to where it was on x and y, at 0, 0, it shows that ball lands at 0.248107805848122, 0.248107805848122, 0. Why the discrepancy? Shouldn't it travel the same exact distance on each side? Numbers are immutable, as is the math done upon those numbers. 2 plus 2 will always be four, 2 times 2 will always be 8, and so on. I don't understand the discrepancy here, since the only thing that I did was exactly mirror the previous shot, with no other changes. It should be like driving a car to the store down the street, then back home, the same distance for both, right? These sort of discrepancies are what cause the problem I have that has forced me to entirely rewrite this code in the first fucking place. I thought that using vectors and applying actual immutable math equations to this would stop this sort of shit. So what the fuck is causing the discrepancy now?
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