Team,
Can someone help clarify the ip add assignment on R6 and R9, Task 2-2 LAB5-
Vol2 DSG?
We are give the subnet 172.16.69.0/30 to be used and we have 4 interfaces
(s0/2/0, s0/2/1) on both R6 and R9.
This is my understanding:
1- The subnet gives us 4 ip addresses: 172.16.69.0, 172.16.69.1, 172.16.69.2,
172.16.69.3, with .0 and .3 being subnet and broadcast address
respectively.
There is 2 approaches here:
a) If I did not have the restriction to use /30 subnet, I would open up the
range and I would use a /29 subnet, which would give me enough [6 usable] ip
addresses to assign to my 4 interfaces.
b) Since I have the /30 restriction in place I will use the 4 ip addresses
indicated above for my 4 serial interfaces [provided ip classless is in place],
and this allows me to do the following:
In R6:
int s0/2/0
ip add 172.16.69.0 255.255.255.252
int s0/2/1
ip add 172.16.69.2 255.255.255.252
In R9:
int s0/2/0
ip add 172.16.69.1 255.255.255.252
int s0/2/1
ip add 172.16.69.3 255.255.255.252
The solution assigns the same ip add [172.16.69.0 255.255.255.254] to both
s0/2/0 and s0/2/1 on R6, and the remaining (.1 and .3 ) are assigned to R9.
My obvious question are:
- Can we do this on R6? The .2 has not even been used but s0/2/0 and s0/2/1
share the same ip add [.0] on R6....
- Why change the mask to 255.255.255.254 (/31) ? The requirement is to use /30.
Thanks
B.
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