The solution is wrong and this is becoming real embarressement. Se0/2/1 on
R6 should be configured as:

int ser0/2/1
 ip address 172.16.69.2 255.255.255.254
!

However, I think the question may have been misunderstood by the person
solving the lab in a sense that there are two obvious solutions - one is to
subnet /30 into two /31 subnets and the other one is to create multilink PPP
between R6 and R9 and use /30 mask.

I will talk to the original developer to take a closer look. This has, for
now, been changed in our development copy to 2x /31.

Keep up the good work, Bauke!

--
Marko Milivojevic - CCIE #18427
Senior Technical Instructor - IPexpert

Mailto: [email protected]
Telephone: +1.810.326.1444
Fax: +1.810.454.0130
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On Wed, Dec 30, 2009 at 01:24, Bauke Dzavhale <[email protected]
> wrote:

> Team,
>
> Can someone help clarify the ip add assignment on R6 and R9, Task 2-2 LAB5-
> Vol2 DSG?
>
> We are give the subnet 172.16.69.0/30 to be used and we have 4 interfaces
> (s0/2/0, s0/2/1) on both R6 and R9.
> This is my understanding:
>
> 1- The subnet gives us 4 ip addresses: 172.16.69.0, 172.16.69.1,
> 172.16.69.2, 172.16.69.3,  with *.0*   and  * .3*   being subnet and
> broadcast address respectively.
>
> There is 2 approaches here:
> a) If I did not have the restriction to use /30 subnet, I would open up the
> range and I would use a /29 subnet, which would give me enough [6 usable] ip
> addresses to assign to my 4 interfaces.
> b) Since I have the /30 restriction in place I will  use the 4 ip addresses
> indicated above for my 4 serial interfaces [provided ip classless is in
> place], and this allows me to do the following:
>
> In R6:
> int s0/2/0
>      ip add 172.16.69.0   255.255.255*.252*
>
>      int s0/2/1
>      ip add 172.16.69.*2  *  255.255.255.*252*
>
>
> In R9:
> int s0/2/0
>      ip add 172.16.69*.1*   255.255.255.*252*
>
>      int s0/2/1
>      ip add 172.16.69.3* *   255.255.255.*252*
>
> The solution assigns the same ip add [172.16.69.*0  * 255.255.255.*254*]
> to both s0/2/0 and s0/2/1 on R6, and the remaining (.1  and .3 ) are
> assigned to R9.
>
> My obvious question are:
> - Can we do this on R6? The *.2* has not even been used but s0/2/0 and
> s0/2/1 share the same ip add [*.0*]  on R6....
> - Why change the mask to 255.255.255.*254*  (/31) ? The requirement is to
> use /30.
>
>
> Thanks
>
> B.
>
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