I guess with all the corrections Bauke have made to the workbooks he
deserves some proctor labs sessions for free :)




On Tue, Dec 29, 2009 at 10:03 PM, Marko Milivojevic <[email protected]>wrote:

>
> The solution is wrong and this is becoming real embarressement. Se0/2/1 on
> R6 should be configured as:
>
> int ser0/2/1
>  ip address 172.16.69.2 255.255.255.254
> !
>
> However, I think the question may have been misunderstood by the person
> solving the lab in a sense that there are two obvious solutions - one is to
> subnet /30 into two /31 subnets and the other one is to create multilink PPP
> between R6 and R9 and use /30 mask.
>
> I will talk to the original developer to take a closer look. This has, for
> now, been changed in our development copy to 2x /31.
>
> Keep up the good work, Bauke!
>
>  --
> Marko Milivojevic - CCIE #18427
> Senior Technical Instructor - IPexpert
>
> Mailto: [email protected]
> Telephone: +1.810.326.1444
> Fax: +1.810.454.0130
> Community: http://www.ipexpert.com/communities
>
>   On Wed, Dec 30, 2009 at 01:24, Bauke Dzavhale <
> [email protected]> wrote:
>
>>     Team,
>>
>> Can someone help clarify the ip add assignment on R6 and R9, Task 2-2
>> LAB5- Vol2 DSG?
>>
>> We are give the subnet 172.16.69.0/30 to be used and we have 4 interfaces
>> (s0/2/0, s0/2/1) on both R6 and R9.
>> This is my understanding:
>>
>> 1- The subnet gives us 4 ip addresses: 172.16.69.0, 172.16.69.1,
>> 172.16.69.2, 172.16.69.3,  with *.0*   and  * .3*   being subnet and
>> broadcast address respectively.
>>
>> There is 2 approaches here:
>> a) If I did not have the restriction to use /30 subnet, I would open up
>> the range and I would use a /29 subnet, which would give me enough [6
>> usable] ip addresses to assign to my 4 interfaces.
>> b) Since I have the /30 restriction in place I will  use the 4 ip
>> addresses indicated above for my 4 serial interfaces [provided ip classless
>> is in place], and this allows me to do the following:
>>
>> In R6:
>> int s0/2/0
>>      ip add 172.16.69.0   255.255.255*.252*
>>
>>      int s0/2/1
>>      ip add 172.16.69.*2  *  255.255.255.*252*
>>
>>
>> In R9:
>> int s0/2/0
>>      ip add 172.16.69*.1*   255.255.255.*252*
>>
>>      int s0/2/1
>>      ip add 172.16.69.3* *   255.255.255.*252*
>>
>> The solution assigns the same ip add [172.16.69.*0  * 255.255.255.*254*]
>> to both s0/2/0 and s0/2/1 on R6, and the remaining (.1  and .3 ) are
>> assigned to R9.
>>
>> My obvious question are:
>> - Can we do this on R6? The *.2* has not even been used but s0/2/0 and
>> s0/2/1 share the same ip add [*.0*]  on R6....
>> - Why change the mask to 255.255.255.*254*  (/31) ? The requirement is to
>> use /30.
>>
>>
>> Thanks
>>
>> B.
>>
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>
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