Well by time I nail my written in a couple weeks and get to these, the kinks will be worked out :)
--- On Tue, 12/29/09, Marko Milivojevic <[email protected]> wrote: From: Marko Milivojevic <[email protected]> Subject: Re: [OSL | CCIE_RS] ip addressing @ R6 and R9, Task 2-2 LAB5- Vol2 DSG... To: "Bauke Dzavhale" <[email protected]> Cc: [email protected] Date: Tuesday, December 29, 2009, 6:03 PM The solution is wrong and this is becoming real embarressement. Se0/2/1 on R6 should be configured as: int ser0/2/1 ip address 172.16.69.2 255.255.255.254 ! However, I think the question may have been misunderstood by the person solving the lab in a sense that there are two obvious solutions - one is to subnet /30 into two /31 subnets and the other one is to create multilink PPP between R6 and R9 and use /30 mask. I will talk to the original developer to take a closer look. This has, for now, been changed in our development copy to 2x /31. Keep up the good work, Bauke! -- Marko Milivojevic - CCIE #18427 Senior Technical Instructor - IPexpert Mailto: [email protected] Telephone: +1.810.326.1444 Fax: +1.810.454.0130 Community: http://www.ipexpert.com/communities On Wed, Dec 30, 2009 at 01:24, Bauke Dzavhale <[email protected]> wrote: Team, Can someone help clarify the ip add assignment on R6 and R9, Task 2-2 LAB5- Vol2 DSG? We are give the subnet 172.16.69.0/30 to be used and we have 4 interfaces (s0/2/0, s0/2/1) on both R6 and R9. This is my understanding: 1- The subnet gives us 4 ip addresses: 172.16.69.0, 172.16.69.1, 172.16.69.2, 172.16.69.3, with .0 and .3 being subnet and broadcast address respectively. There is 2 approaches here: a) If I did not have the restriction to use /30 subnet, I would open up the range and I would use a /29 subnet, which would give me enough [6 usable] ip addresses to assign to my 4 interfaces. b) Since I have the /30 restriction in place I will use the 4 ip addresses indicated above for my 4 serial interfaces [provided ip classless is in place], and this allows me to do the following: In R6: int s0/2/0 ip add 172.16.69.0 255.255.255.252 int s0/2/1 ip add 172.16.69.2 255.255.255.252 In R9: int s0/2/0 ip add 172.16.69.1 255.255.255.252 int s0/2/1 ip add 172.16.69.3 255.255.255.252 The solution assigns the same ip add [172.16.69.0 255.255.255.254] to both s0/2/0 and s0/2/1 on R6, and the remaining (.1 and .3 ) are assigned to R9. My obvious question are: - Can we do this on R6? The .2 has not even been used but s0/2/0 and s0/2/1 share the same ip add [.0] on R6.... - Why change the mask to 255.255.255.254 (/31) ? The requirement is to use /30. Thanks B. All new Yahoo! Mail - Get a sneak peak at messages with a handy reading pane. _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com -----Inline Attachment Follows----- _______________________________________________ For more information regarding industry leading CCIE Lab training, please visit www.ipexpert.com
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