While I recognize many of the Cisco questions are terrible about
being precise in their terminology, it's a slight help -- and every
bit helps -- to make a point of avoiding the word "network," and
possibly "subnet," in a classless environment.
As many people have said, the answer is not in the octets, but is in
the bits (sounds vaguely Shakespearean). From my own experience,
it's far more effective to find the answer by playing with the prefix
lengths rather than the octets.
Q3 is terribly written, because the only information it gives you on
prefix length is the classful implied length of /24. But under
clasless terminology, the question _could_ be referring to:
> > 192.168.9.0/28
> > 192.168.10.0/26
> > 192.168.11.0/24
> 192.168.12.0/27
for which summarization could not work.
A way to pose what I think the real question is:
"You have four /24 prefixes. If they are contiguous, what would be
the prefix length of the supernet that appropriately aggregates them?
What would the supernet address be?"
>Answer for the question 1 is B and I can prove it.
>
>Our subnet mask is 255.255.240.0 => which means 4 bits from the
>third octet are
>used for the subnet masking.
>That gives us the interval of 16 between the two networks.
>Following will be the networks for the subnet mask
>
>10.6.16.0 Host range 10.6.16.1 - 10.6.31.254 B'cast Address 10.6.31.255
>10.6.32.0 10.6.32.1 - 10.6.47.254 10.6.47.255
>10.6.48.0 10.6.48.1 - 10.6.63.254 10.6.63.255
>10.6.64.0 10.6.64.1 - 10.6.95.254 10.6.95.255
>and so on......... until
>10.6.224.0
>
>Thus our answer is 10.6.32.0, 10.6.47.255
>
>Any more specifics, let me know I will explain.
>
>Then Hunt go through the TCP\IP subnetting and supernetting from as many books
>as possible until you feel comfortable. Any other help you need let me know.
>
>Rajeev Soni
>
>____________________Reply Separator____________________
>Subject: Re: Subnet questions
>Author: Andy <[EMAIL PROTECTED]>
>Date: 2/3/2001 5:40 PM
>
>
>
>On Sun, 4 Feb 2001, Hunt Lee wrote:
>
>> I have three subnet / route summarization questions but I don't
>> understand the answer, any help would be greatly appreciated.
>>
>> Q1)ннн Choose the appropriate classless network address and broadcast
>> address for the IP address 10.6.38.50 with a subnet mask of
>> 255.255.240.0
>>
>> A)ннн 10.6.38.49 and 10.6.38.62
>>
>> B)ннн 10.6.32.0 and 10.6.47.255
>>
>> C)ннн 10.6.38.0 and 10.6.38.255
>>
>> D)ннн 10.0.0.0 and 10.255.255.255
>>
>> Answer is B.
>
>No its not. The answer is 10.6.38.48 and 10.6.38.63. It probably meant to
>say classful.
>
>> Q2)ннн Given a classless route summarization of 72.8.0.0 /13.н Which IP
>> address fall into this scope?
>>
>> A)ннн 72.15.36.8
>>
>> B)ннн 72.13.1.1
>>
>> C)ннн 72.8.20.10
>>
>> D)ннн 72.7.200.100
>>
>> E)ннн 72.16.7.4
>>
>> F)ннн 72.40.1.8
>>
>> Answer is A, B & C - why isn't E the ansewr as well?
>
>The range of 72.8.0.0/13 is 72.8.0.0 - 72.15.255.255. Its 8 Class B's.
>
>> Q3)ннн When using classless supernetting, which route best summarizes
>> the following networks?
>>
> > 192.168.9.0
>> 192.168.10.0
>> 192.168.11.0
> > 192.168.12.0
>>
>> A)ннн 192.168.0.9 / 20
>>
>> B)ннн 192.168.0.0 / 16
>>
>> C)ннн 192.168.9.0 / 22
>>
>> D)ннн 192.168.8.0 / 21
>>
>> I thought D is the answer, but the answer is C.
>
>A /22 is 4 Class C's, a /21 is 8. I recommand finding or making (to
>actually learn it) a subnet table and just keeping referencing it until
>you don't need to anymore.
>
>andy
>
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>Subject: Re: Subnet questions
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