Answer for the question 1 is B and I can prove it.
Our subnet mask is 255.255.240.0 => which means 4 bits from the third octet are
used for the subnet masking.
That gives us the interval of 16 between the two networks.
Following will be the networks for the subnet mask
10.6.16.0 Host range 10.6.16.1 - 10.6.31.254 B'cast Address 10.6.31.255
10.6.32.0 10.6.32.1 - 10.6.47.254 10.6.47.255
10.6.48.0 10.6.48.1 - 10.6.63.254 10.6.63.255
10.6.64.0 10.6.64.1 - 10.6.95.254 10.6.95.255
and so on......... until
10.6.224.0
Thus our answer is 10.6.32.0, 10.6.47.255
Any more specifics, let me know I will explain.
Then Hunt go through the TCP\IP subnetting and supernetting from as many books
as possible until you feel comfortable. Any other help you need let me know.
Rajeev Soni
____________________Reply Separator____________________
Subject: Re: Subnet questions
Author: Andy <[EMAIL PROTECTED]>
Date: 2/3/2001 5:40 PM
On Sun, 4 Feb 2001, Hunt Lee wrote:
> I have three subnet / route summarization questions but I don't
> understand the answer, any help would be greatly appreciated.
>
> Q1) Choose the appropriate classless network address and broadcast
> address for the IP address 10.6.38.50 with a subnet mask of
> 255.255.240.0
>
> A) 10.6.38.49 and 10.6.38.62
>
> B) 10.6.32.0 and 10.6.47.255
>
> C) 10.6.38.0 and 10.6.38.255
>
> D) 10.0.0.0 and 10.255.255.255
>
> Answer is B.
No its not. The answer is 10.6.38.48 and 10.6.38.63. It probably meant to
say classful.
> Q2) Given a classless route summarization of 72.8.0.0 /13. Which IP
> address fall into this scope?
>
> A) 72.15.36.8
>
> B) 72.13.1.1
>
> C) 72.8.20.10
>
> D) 72.7.200.100
>
> E) 72.16.7.4
>
> F) 72.40.1.8
>
> Answer is A, B & C - why isn't E the ansewr as well?
The range of 72.8.0.0/13 is 72.8.0.0 - 72.15.255.255. Its 8 Class B's.
> Q3) When using classless supernetting, which route best summarizes
> the following networks?
>
> 192.168.9.0
> 192.168.10.0
> 192.168.11.0
> 192.168.12.0
>
> A) 192.168.0.9 / 20
>
> B) 192.168.0.0 / 16
>
> C) 192.168.9.0 / 22
>
> D) 192.168.8.0 / 21
>
> I thought D is the answer, but the answer is C.
A /22 is 4 Class C's, a /21 is 8. I recommand finding or making (to
actually learn it) a subnet table and just keeping referencing it until
you don't need to anymore.
andy
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