>Right, I am speaking of the process between end stations here. My thinking
>is, if the router discarded the frame, then the originating station would
>not get an ack out of sequence from the remote end station because the
>packet was dropped (therefore the remote never got something to ack).
>
>The originating station would actually retransmit because it did not get an
>ack from the remote.
>
>Right?
>
> Unless TCP has negotiated that x number of packets can be transmitted w/o
>an ack. Which I know can be done, but don't know how common it is.
Not the number of packets, but the number of bytes. The usual
practice is to use a slow start mechanism, where TCP starts with one
byte per ACK, then keeps increasing the window until delay or
congestion limits performance (vast simplification).
>
>
>
>-----Original Message-----
>From: Howard C. Berkowitz [mailto:[EMAIL PROTECTED]]
>Sent: Friday, February 09, 2001 10:06 AM
>To: [EMAIL PROTECTED]
>Subject: RE: not quite sure...
>
>
>>In the discussion of error correction, I think an error on my part has been
>>missed. I was thinking about it and I wonder if this is entirely accurate:
>>
>>(concerning what happens after a frame is discarded on WAN link)
>>
>>"The end station will respond by acking the next packet it recieves with
>the
>>appriopriate (lower numbered) sequence number (of the missed packet). The
>>originating station will
>>get this ack (with the lower sequence number) see that the end station is
>>requesting a packet out of sequence and the originating station will begin
>>it's next transmission with the data from that particular sequence number."
>>
>>Is this correct?
>
>
>Emphasis: end station. You are describing what TCP does. Routers
>typically are unconcerned with TCP.
>
>And again, not all applications need reliable links, so not all
>applications will have retransmission ANYWHERE in the path.
>
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