The TX/RX "loopback" is inside the NIC, from what I understand. I don't
think the senders see each other's transmissions even though their TX wires
end up being the same wire past the splitter. But I always try to work above
the physical layer and may be missing something.

Well, it's time to move on. Enjoy your Miller. ;-)

Priscilla

s vermill wrote:
> 
> Priscilla Oppenheimer wrote:
> > 
> > s vermill wrote:
> > > 
> > > Priscilla Oppenheimer wrote:
> > > > 
> > > > Back to the Ethernet question. Does the splitter simply
> take
> > > > the four wires that 10BaseT uses and make 2 wires out of
> > each,
> > > > sending one of each to each port? What an awful thing to
> do
> > to
> > > > an Ethernet! You bad boys. ;-)
> > > 
> > > Quite devious indeed!  And yes, the splitter has one male
> > RJ-45
> > > and a modular body that has two female RJ-45s pointing in
> the
> > > opposite direction.  Pin 1 from the male goes to pin 1 of
> both
> > > females, etc.
> > > 
> > > > 
> > > > As Scott mentioned, some books make it sound like the
> sender
> > > > loops back what it sends so that it can compare that with
> > what
> > > > it receives back from the hub, sort of implying that the
> hub
> > > > sends back the transmitter's bits to the transmitter. A
> hub
> > > > doesn't do that. And the loopback isn't used to do a
> > bit-wise
> > > > comparison with what the hub is sending, like some books
> > > imply.
> > > > That would be computationally expensive and also isn't
> > > > necessary. Simply receiving while you are sending means a
> > > > collision occurred.
> > > 
> > > I gave this some thought on my drive home.  I've read that
> > NICs
> > > internally bridge tx to rx.  According to this theory, a
> > > comparator circuit outputs zero as long as what is on tx is
> > > also on rx.  If someone else collides, the comparator
> outputs
> > > something other than zero, because what is on rx is now a
> > > combination of the colliding signal and what tx was
> > > outputting.  Does that make sense?  I realize this may be
> > urban
> > > myth 
> > 
> > I've seen this in books also. It may be true. But I also
> > noticed that Odom backed off (so to speak) on how he explains
> > this. I used to have an old copy of his CCNA book for
> teaching.
> > In the new edition, he has changed that discussion.
> > 
> > > (especially since, as you pointed out, this is a lot more
> > > expensive than just declaring a collision if you rx while
> > > tx'ing), but it would be interesting if some or all NICs
> > > actually did this.  Because then, although CSMA/CD still
> > > wouldn't work for the reasons already mentioned, the
> collision
> > > between the two stations would be detected and backoff would
> > > take place.  Otherwise, it would be up to upper layer
> > protocols
> > > to retrans.
> > 
> > The two stations still wouldn't see each other.
> 
> Consider that the two tx leads physically tie together.  So if
> both stations were to transmit simultaneously, each would have
> a comparator that is expecting just the one transmitted
> signal.  What would show up on the bridged rx lead would be the
> mess that the colliding signals created.  They otherwise
> wouldn’t "see" one another.
> 
> But we digress.  Hubs are, of course, on the way out the door
> and this is a bad practice anyway.  Before traveling, I used to
> upload all of my in-progress files to a network share and then
> log my laptop in using the splitter just long enough to pull
> them back down (i.e. I was lazy).  I would then do the inverse
> upon return.  Just goes to show what happens when you let a WAN
> jock play on the LAN!  (I'm semi-reformed at this stage and
> acknowledge my debt to society)
> 
> > 
> > The books that are wrong, by the way, make it sound like the
> > hub sends back to the transmitter, which it doesn't. Are you
> > implying that it would in this case? I don't think it would.
> 
> No, that wouldn't make any sense.  Regardless of how NICs
> determine a collision condition, it wouldn't work that a hub
> repeat back on the transmitting port.  I was thinking outlout a
> post or two back.
> 
> Miller time(r)...
> 
> Scott
> 
> 




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