""B.J. Wilson""  wrote in message
[EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> You sure about that, Chuck? ;-)


CL: well..... yeah I understand the subnet zero argument. It's been too long
since I studied anything from a CCNA level.

CL: to be truthful, I have never bothered with the 2n-2 issue in real world
or in my CCIE studies. ip subnet-zero renders that irrelevant.

CL: If I don't pass my lab next time, I am facing a CCNP/DP recert, so I
guess I should keep that in mind ;->


>
> 2^n-2 = 8  ! a total of 8 subnets needed !
> 2^n = 10   ! add 2 to both sides !
> n = 4      ! 2^4-2 = 14 !
>
> 128 64 32 16 8 4 2 1
>  1   1  1  1 0 0 0 0
>
> = 240, or answer A in the original post.
>
> BJ
>
>
>
> -------Original Message-------
> From: The Long and Winding Road
> Sent: 12/05/02 09:48 AM
> To: [EMAIL PROTECTED]
> Subject: Re: VLSM Question [7:58569]
>
> > you sure about that, Tom?
>
>
> 172.100.00000000.0
> 255.255.11100000.0
> subnet bits = 11111.0
> 172.100.0.0 through 172.100.31.0 for /24's
>
> these would be SUMMARIZED using the 224 mask in the third octet.
>
> if you only want eight /24's, then the answer is
>
> 172.100.00000000.0
> 255.255.11111000.0
> subnet bits =     111     eight subnets of /24
> summarized as 172.100.0.0/21 ( 248 )
>
>
>
> --
> TANSTAAFL
> "there ain't no such thing as a free lunch"
>
>
>
>
> ""Tom Lisa""  wrote in message
> [EMAIL PROTECTED]">news:[EMAIL PROTECTED]...
> > If the test prep you are using is for the CCNA exam then "C" is the
> > correct
> > "Cisco" answer (the use of Class B/Class C terminology makes me think
> > this is the case). This is because Cisco still insists, at the CCNA
> > level, on
> > computing subnets using the formula 2^n-2.  This assumes that subnet
> > zero and the all ones subnet are unusable.  Therefore you have to create
> > 16 subnets, resulting in 14 "usable" to get the required 8 subnets.
> >
> > In the "real" world, 255.255.224.0 is correct.
> > BTW, what is the VLSM question here?
> >
> > HTH,
> > Prof. Tom Lisa, CCAI
> > Community College of Southern Nevada
> > Cisco ATC/Regional Networking Academy
> > "Cunctando restituit rem"
> >
> > Richard Burdette wrote:
> >
> >   A prep test I am using has a question for which I disagree with the
> >   answer.
> >   Here is the question
> >
> >   If I had a Class B address, what subnet mask would I use if I wanted
> >   to
> >   split it into 8 class C addresses?
> >
> >   a.255.255.240.0
> >   b.255.255.255.0
> >   c.255.255.248.0
> >   d.255.255.254.0
> >
> >   The answer from the test is c.
> >
> >   I think the answer is not even listed; 255.255.224.0 because to add
> >   eight
> >   additional subnets we need 2^3=8 bits of subnet which equates to 224
> >   of
> >   mask.  Am I right or wrong?
> >
> >   Rich
> >
> >
> >
> >
> >   [EMAIL PROTECTED]




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