FWIW, the same is true for the inverse operation. 

If you pop an item off a list you’ll get the list, less the item you conj’d. 
Same is true with a vector. 

---
Joe R. Smith
j...@uwcreations.com <mailto:j...@uwcreations.com> 
@solussd


On Jul 16, 2018, at 4:31 PM, Alex Miller <a...@puredanger.com 
<mailto:a...@puredanger.com> > wrote:



On Monday, July 16, 2018 at 4:08:47 PM UTC-5, solussd wrote:
Another way to think about it is lists and vectors are different and the 
idiomatic way to add items to them is different. 

I would say different data structures have different ways to *efficiently* add 
items to them, and conj is an operation to add items efficiently (meaning, 
sub-linear time). So when you see conj, you know it is always a "fast" 
operation. 
 A (singly-linked) list is usually prepended to (otherwise you have to walk the 
entire list to find the end). A vector is usually added to at it’s n+1 index, 
where n is the size of the vector. The conj function is polymorphic.

cons takes a seq and returns a seq. It only cares that it can get a seq on 
whatever collection you give it and will always prepend to that seq.

Slight modification - I would say cons takes a *seqable* and returns a seq. For 
example, a vector is seqable, but not a seq.

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