Yes sorry, I was looking to initialize to the default value of
node. Thank you for the help!
On Saturday, 31 March 2012 at 21:59:50 UTC, Ali Çehreli wrote:
On 03/31/2012 02:34 PM, Chris Pons wrote:
> I'm trying to figure out how to initialize a
multi-dimentional array
> with a struct. I thought it would be straight forward, but
i'm running
> into problems. I'm using nested for loops, and just setting
the current
> index to a blank version of my struct but that gives me this
error:
> "Error: no [] operator overload for type Node". I didn't know
I needed
> to overload that operator, usually didn't need to in C++ as
far as I
> remember.
>
> struct Node
> {
> bool walkable;
> vect2 position;
> int xIndex, yIndex;
> Node*[4] connections;
> }
>
> void InitializePathGraph()
> {
> for( int x = 0; x < mapWidth; x++ )
> {
> for( int y = 0; y < mapHeight; y++ )
> {
> Node node;
> PathGraph[x][y] = node;// ERROR
> }
> }
> }
>
>
Do you want to initialize with the default value of Node? Then
it is as easy as the following:
import std.stdio;
struct Node
{}
void main()
{
Node[2][3] a; // fixed-length of fixed-length
Node[][] b = new Node[][](2, 3); // slice of slice
writeln(a);
writeln(b);
}
The output:
[[Node(), Node()], [Node(), Node()], [Node(), Node()]]
[[Node(), Node(), Node()], [Node(), Node(), Node()]]
Please note the different meanings of 2 and 3 for the
fixed-length array and the new expression: lines and rows are
swapped!
Ali
