Well, yes.  the mean and standard deviation are not 'linked' for data with a
Normal distribution.

Dale Glaser asked:

Well, what about the standard normal distribution: N(0,1)?

The mean is 0, the standard deviation, 1.

If you add the restriction that the data not be less than 0, and allow a
severe skew (relax the Normal dist. requirement), then Ken Beath and others
showed that yes, certainly, s can be larger than x-bar (or sigma > mu, if you
prefer).

Since the Poisson distribution _is_ linked, so that the mean equals the
variance, then for an equivalent distribution (log-normal?), one sould expect
that for mu values less than 1, the sigma (sqrt(var)) will be greater than the
mean.

Jay

Edward Dreyer wrote:

> A colleague of mine - not a subscriber to this helpful list - asked me if
> it is possible for the standard deviation
> to be larger than the mean.  If so, under what conditions?
>
> At first blush I do not think so  --------- but then I believe I have seen
> some research results in which standard deviation was larger than the mean.
>
> Any help will be greatly appreciated..
> cheers....ECD
>
> ___________________________
>
> Edward C. Dreyer
> Political Science
> The University of Tulsa
> ________________________
>
> =================================================================
> Instructions for joining and leaving this list and remarks about
> the problem of INAPPROPRIATE MESSAGES are available at
>                   http://jse.stat.ncsu.edu/
> =================================================================

--
Jay Warner
Principal Scientist
Warner Consulting, Inc.
4444 North Green Bay Road
Racine, WI 53404-1216
USA

Ph: (262) 634-9100
FAX: (262) 681-1133
email: [EMAIL PROTECTED]
web: http://www.a2q.com

The A2Q Method (tm) -- What do you want to improve today?






=================================================================
Instructions for joining and leaving this list and remarks about
the problem of INAPPROPRIATE MESSAGES are available at
                  http://jse.stat.ncsu.edu/
=================================================================

Reply via email to