Actually 1 ohm of total resistance from a 14V source and a 20A load
would be more than excessive. More like a 0.01 ohm is 0.20 volt drop
for 20 amps. I x R = E
View it as 3 series resistors across a 14 V source. R-1 is the DC POS
lead resistance, the radio which is a variable resistance as R-2, and
R-3 which is the DC NEG lead resistance. Therefore, the voltage at the
radio is equal to the IR drop being the sum of R-1 and R-3.
73
Bob, K4TAX
On 12/28/2019 11:26 AM, Michael Walker wrote:
For measuring voltage drop.. I would measure the voltage drop from the Plus
lead of the Power supply to the plus lead on the back of the radio while in
full load TX (FM or RTTY).
It should be less than 0.1 or 0.2 of a volt.
Then, do the same on the Negative Lead. You should see the same answer
(assuming Negative DC doesn't find an alternative path).
Those numbers should add up to the same voltage drop total.
As a reminder. It only takes 1 ohm of loss in the cable/fuses to
significantly impact your full power out.
Mike va3mw
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