Dear John B. Hodges, the following example demonstrates that Bucklin violates consistency.
Situation 1:
4 A > B > C
5 B > C > A
6 C > A > B
Candidate C is the unique Bucklin winner.
Situation 2:
4 A > B > C
5 C > A > B
Candidate C is the unique Bucklin winner.
Situation 1+2:
Candidate A is the unique Bucklin winner.
Markus Schulze
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