Dear Kevin, you wrote (2 Sep 2003): > I think MCA meets Clone Independence and Participation, > but I'd like to hear reasoning to the contrary.
Situation 1: 2 A > B > C 3 B > C > A 4 C > A > B The winner is candidate C. Situation 2: Replacing C by C1, C2, and C3 gives: 2 A > B > C2 > C1 > C3 3 B > C3 > C2 > C1 > A 4 C1 > C2 > C3 > A > B The winner is candidate B. Markus Schulze ---- Election-methods mailing list - see http://electorama.com/em for list info
