On 02/03/2012 08:45 PM, Andy Jennings wrote:

- If someone built a computer program that presented me pairs of
candidates at a time as Kristofer suggested, that would make it somewhat
easier.  I think I would still prefer to divide them into tiers first,
but if I divided them into tiers first, I might not need the pairwise
comparison hand-holding.  Also, suppose that I analyzed the candidates
in three different policy dimensions that I consider equally important
and I found that my policy preferences were:
Foreign Policy: A>B>C
Domestic Social Issues: B>C>A
Domestic Economic Issues: C>A>B
Now I prefer A to B, B to C, and C to A.  A cycle among my own personal
preferences when I compare them pairwise.  Then my output ranking would
depend on the order in which the pairwise questions were asked.  ??!?

You could look at a (single-winner) voting method as a stand-in for a deliberative process. A ranked voting method tries to find the best common ranking given the data it has to go on, which are the votes themselves.

In the ideal case, you'd just have a deliberative process instead of the voting. There would be some back-and-forth and then you'd reach a consensus. The problem is that it doesn't scale.

But if a voting method is a stand-in for a deliberative process, then it makes sense that each voter's preference would be transitive. The voters would already have gone through an internal deliberative process to arrive at a ranking of the candidates they are considering. So if I'm right about that, then the voter would already know his own consensus ranking based on the "foreign vs social vs economic" tradeoffs and the relative weights they have to him.

In practice, things aren't that clean, but I think it works to show, intuitively, that people would have transitive rankings and so wouldn't encounter the internal cycle problem.

If a voter's internal ranking is transitive, then you would only need to ask him "X better than Y?" n lg n times for n candidates*, where lg is the base-2 logarithm. If not, you would have to ask him n^2 times. Condorcet-type methods could handle both cases - in the latter, n^2 case, a pairwise method would incorporate intra-individual cycles by the exact same logic as it'd handle inter-individual cycles.

(As I have said before, I have been thinking about using Condorcet methods for getting a ranking out of preference comparisons where the individual may have internal cycles because the set is so large. Ranking pictures is a simple example of that, as there may be so many pictures that the person looks at different things when comparing X to Y than when comparing Y to Z. However, doing n^2 comparisons grows very quickly and becomes quite tiresome. Some amount of preprocessing may speed it up - like your "tiers" or an Approval first stage where the person is generous with the approvals but excludes that which he considers obviously uninteresting.)

* The simplest algorithm that achieves this bound is, in essence, an insertion sort that uses a binary search for each insertion. Its constant factor is better than say, quicksort, too, since all we care about is the number of comparisons, not the time it takes to insert.

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