On 3/4/2020 5:25 PM, Bruce Kellett wrote:
On Thu, Mar 5, 2020 at 11:59 AM 'Brent Meeker' via Everything List
<everything-list@googlegroups.com
<mailto:everything-list@googlegroups.com>> wrote:
On 3/4/2020 4:34 PM, Bruce Kellett wrote:
The crux of the matter is that all branches are equivalent when
both outcomes occur on every trial, so all observers will infer
that their observed relative frequencies reflect the actual
probabilities. Since there are observers for all possibilities
for p in the range [0,1], and not all can be correct, no sensible
probability value can be assigned to such duplication experiments.
The problem is even worse in quantum mechanics, where you measure
a state such as
|psi> = a|0> + b|1>.
When both outcomes occur on every trial, the result of a sequence
of N trials is all possible binary strings of length N, (all 2^N
of them). You then notice that this set of all possible strings
is obtained whatever non-zero values of a and b you assume. The
assignment of some propbability relation to the coefficients is
thus seen to be meaningless -- all probabilities occur equal for
any non-zero choices of a and b.
But E(number|0>) = aN
Where does this come from? The weight of each branch is a^x*b^y for a
branch with x zeros and y ones.
But this weight is external to the branch, and the 1p probability
estimates from within the branch are necessarily independent of the
overall coefficient. The expectation for the number of zeros within
any branch depends on the branch, but is independent of both a and b.
Sorry, I see I didn't make it clear I was assuming the Born rule. I was
just pointing out that this makes an assignment of probabilities to the
multiple worlds which is the same as looking at a single world as a
member of an ensemble.
Brent
I suspect that you are mixing the 1p and 3p viewpoints. Or else you
are using the expectation for a single outcome per trial (not that for
which both outcomes occur on every trial.)
Bruce
and Var(number|0>) = abN. The fraction x within one
std-deviation of the expected number is a constant
F( a-sqrt[ab/N]<x<a+sqrt[ab/N])=1/e
So that fraction become more an more sharply confined around a as
N->oo.
Brent
--
You received this message because you are subscribed to the Google
Groups "Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send
an email to everything-list+unsubscr...@googlegroups.com
<mailto:everything-list+unsubscr...@googlegroups.com>.
To view this discussion on the web visit
https://groups.google.com/d/msgid/everything-list/CAFxXSLQRTO79k1M5P8LcQLJBqWhop_Hw9Ti6%2BrnTjR38yuT0CQ%40mail.gmail.com
<https://groups.google.com/d/msgid/everything-list/CAFxXSLQRTO79k1M5P8LcQLJBqWhop_Hw9Ti6%2BrnTjR38yuT0CQ%40mail.gmail.com?utm_medium=email&utm_source=footer>.
--
You received this message because you are subscribed to the Google Groups
"Everything List" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to everything-list+unsubscr...@googlegroups.com.
To view this discussion on the web visit
https://groups.google.com/d/msgid/everything-list/2224809d-f7b0-20d7-eea7-3cf6dd2f540c%40verizon.net.
