You claim to be open to mathematical proof, yet you dismiss the arguments without engaging with them. If you were actually willing to read, you'd see that the explanation has already been provided. Since you are so confident that MWI is mathematically refuted, I invite you to publish your formal proof and receive the recognition and applause you believe you deserve.
Quentin Le mar. 18 févr. 2025, 22:49, Bruce Kellett <[email protected]> a écrit : > On Tue, Feb 18, 2025 at 10:11 PM Quentin Anciaux <[email protected]> > wrote: > >> Bruce, >> >> You’re misrepresenting my example. There are still only two possible >> outcomes per trial—seeing 0 or seeing 1. The key difference is that the >> number of observers in each outcome is not equal, which is precisely what >> happens in MWI due to the wavefunction amplitudes. >> >> Your argument relies on counting sequences alone, assuming that all 2^N >> sequences contribute equally to probability estimates. But this is exactly >> the point of contention. In MWI, amplitude determines the number of >> observer instances experiencing each sequence, just as in my thought >> experiment. >> >> Your claim that "each observer sees only one set of data" is trivial—it’s >> true in any probability framework. The issue is why most observers will see >> outcomes that align with the Born rule rather than a uniform 50/50 split. >> >> You state that after N trials, we get all 2^N sequences, regardless of >> amplitudes. But MWI does not say that each sequence has the same >> measure—only that each exists. The assumption that each sequence carries >> equal weight is what you need to prove, not assume. >> >> Your objection about my example "having ten outcomes" misrepresents the >> analogy. There are still only two possible outcomes per trial—the >> difference is that some outcomes have exponentially more observers >> experiencing them. This is exactly how amplitude influences measure in MWI. >> >> Your assertion that "one and only one copy of each outcome is produced" >> contradicts MWI’s entire framework. Unitarity doesn’t create a single copy >> per outcome—it preserves the entire superposition, which includes weighted >> branches. >> >> The fact that amplitudes affect observer frequencies is exactly what >> leads to Born-rule probabilities in MWI, rather than a naive uniform >> distribution. >> >> I'm afraid the sophistry is on your end, there are only two outcomes in >> my observer duplication outcome, seeing 0 or seeing 1. >> >> Your reasoning contains a categorical error: you misinterpret each copy >> as a "distinct outcome," whereas in reality, all copies in the same state >> see the same result. This does not create 10 outcomes but only two, with an >> asymmetric distribution of observers. >> >> Your reasoning is essentially saying "everything that exists must count >> equally," which is a circular assumption and has never been a property of >> quantum mechanics. >> >> So no, there are only two possible outcomes in my example, and your >> objection is invalid. >> > > > Starting from the two-component state that I have been talking about: > > |psi> = a|0> + b|1> > > and using only unitary evolution and the Schrodinger equation, I invite > you to prove mathematically the various claims that you have been making. > > Bruce > > -- > You received this message because you are subscribed to the Google Groups > "Everything List" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To view this discussion visit > https://groups.google.com/d/msgid/everything-list/CAFxXSLTBkeiROqN%2BzHgL6supU9j%3DEKCwSXmu_JxRNvYz6cD-vw%40mail.gmail.com > <https://groups.google.com/d/msgid/everything-list/CAFxXSLTBkeiROqN%2BzHgL6supU9j%3DEKCwSXmu_JxRNvYz6cD-vw%40mail.gmail.com?utm_medium=email&utm_source=footer> > . > -- You received this message because you are subscribed to the Google Groups "Everything List" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To view this discussion visit https://groups.google.com/d/msgid/everything-list/CAMW2kApvDdA7YUEGUnNyA01bn8Fmezd9Dfb0mOCYMr4xraO9Kw%40mail.gmail.com.
