I've seen some responses, but can someone give me an explanation for the 2096128 value from the byte level up (I think we can agree on 8 bits per byte for now...)? Because no matter how I count 2096128 doesn't make sense as a 2GB 31 bit addressing maximum value if you get my drift.
Regards, Erik. -----Oorspronkelijk bericht----- Van: IBM Mainframe Discussion List [mailto:ibm-m...@bama.ua.edu] Namens Erik Janssen Verzonden: dinsdag 29 juni 2010 16:08 Aan: IBM-MAIN@BAMA.UA.EDU Onderwerp: TSO region size >> the help panel says that the maximum possible region size is 2096128. This >> is 1 MB less than 2 GB, which would be 2097152. Can somebody tell me why the >> max is not exactly 2GB? ----------------------------------------------------------------- ATTENTION: The information in this electronic mail message is private and confidential, and only intended for the addressee. Should you receive this message by mistake, you are hereby notified that any disclosure, reproduction, distribution or use of this message is strictly prohibited. Please inform the sender by reply transmission and delete the message without copying or opening it. Messages and attachments are scanned for all viruses known. If this message contains password-protected attachments, the files have NOT been scanned for viruses by the ING mail domain. Always scan attachments before opening them. ----------------------------------------------------------------- ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@bama.ua.edu with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
