On Fri, 26 Aug 2011 07:16:18 -0400, Sambataro, Anthony wrote: >Is not the original abend a S322(CPU timeout)?
No. ABEND code: 00000322 Reason code: 00000000 is what LE said. The 322 in bits 20-31 is the user abend code, decimal 802. System abend codes are in bits 8-19. Also, the DUMP bit is not set, so it is unlikely that any attempt to circumvent LE's ESTAEX would provide any useful information. I would go with Skip's suggestion or try to trap a U0802 abend in the job. -- Tom Marchant > >-----Original Message----- >From: Skip Robinson [mailto:jo.skip.robin...@sce.com] >Sent: Thursday, August 25, 2011 6:01 PM >To: IBM-MAIN@bama.ua.edu >Subject: Re: Help with an LE problem > >I've had good luck with COBOL problems by setting a NONPER SLIP trap with >no abend code specified. Just job name. SLIP is supposed to catch the >first abend--before any ESTAE gets control--and produce an SVC dump for >that abend. > >. >. >JO.Skip Robinson >SCE Infrastructure Technology Services >Electric Dragon Team Paddler >SHARE MVS Program Co-Manager >626-302-7535 Office >323-715-0595 Mobile >jo.skip.robin...@sce.com > > > >From: Binyamin Dissen <bdis...@dissensoftware.com> >To: IBM-MAIN@bama.ua.edu >Date: 08/25/2011 02:31 PM >Subject: Help with an LE problem >Sent by: IBM Mainframe Discussion List <IBM-MAIN@bama.ua.edu> > > > >I have a CEEDUMP with > > CEE3250C The system or user abend U 802 R=NULL was issued. > > ABEND code: 00000322 Reason code: 00000000 > >CIB: > > +000000 000F37F8 C3C9C240 00000000 00000000 010C0004 00000000 >00000000 00040CB2 61C3C5C5 |CIB ......................../CEE| > +000020 000F3818 0000000B 000F3908 00040CB2 61C3C5C5 0000000B >00000000 000EF1C8 C0D68988 |............/CEE..........1H.Oih| > +000040 000F3838 00000000 000F1BF8 43D7CADC 000EC478 00000005 >000EF2B8 00000000 00000000 |.......8.P....D.......2.........| > +000060 000F3858 00000000 00000000 00000000 00000000 00000000 >00000000 00000000 00000000 |................................| > +000080 000F3878 - +00009F 000F3897 same as above > +0000A0 000F3898 00000000 00000000 00000000 00000000 80015000 >00000322 00000000 00000000 |..................&.............| > +0000C0 000F38B8 00000000 43D78DFC 000F1BF8 000F1BF8 43D7CADC >00000000 00000000 00000001 |.....P.....8...8.P..............| > +0000E0 000F38D8 000EF1C8 00000005 00000064 FFFFFFFC 00000001 >00000000 00000000 000E98D0 |..1H..........................q.| > +000100 000F38F8 00000012 000EC690 00000000 00000000 E9D4C3C8 >02000001 43D08008 00000000 |......F.........ZMCH............| > >But the neither the PSW nor the registers are consistent with this abend. >The >registers and PSW are consistent with the "Exception" location. > >The ZMCH block has the exception information. > >It is a COBOL program compiled with THREAD. > >I guess I will need a real dump, but have no idea how to trap it - after >all I >do not see an abend. ---------------------------------------------------------------------- For IBM-MAIN subscribe / signoff / archive access instructions, send email to lists...@bama.ua.edu with the message: GET IBM-MAIN INFO Search the archives at http://bama.ua.edu/archives/ibm-main.html
