Might I suggest changing the variable name from A to SQ?
Then you have the calculation of SQ[i] = i * i.

On Fri, Oct 24, 2014 at 9:32 PM, David Crayford <dcrayf...@gmail.com> wrote:
> On 25/10/2014 3:35 AM, Bob Rutledge wrote:
>>
>> I would guess that, as previously suggested,
>>
>> for i = 1, count do a[i]  = a[i] * i end
>>
>> would really rather be
>>
>> for i = 1, count do a[i]  = i * i end
>>
>
> Good eye Bob! When I copy and pasted the snippet into the e-mail it dropped
> the square brackets. When I edited the code I inserted a bug!
>
> Bloody square brackets will be the death of me!
>
>
>> Bob
>>
>> Barkow, Eileen wrote:
>>>
>>> I keep getting this error both in MVS and UNIX.
>>>
>>> LUA: //'xcics.lua4z.samplib(cpu)':4: attempt to perform arithmetic on
>>> field '?   ' (a nil value)  stack traceback:
>>> //'xcics.lua4z.samplib(cpu)':4: in main chunk
>>> ÝC¨: ?  ***
>>> -----Original Message-----
>>> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On
>>> Behalf Of Bass, Walter W
>>> Sent: Friday, October 24, 2014 2:21 PM
>>> To: IBM-MAIN@LISTSERV.UA.EDU
>>> Subject: Re: [ANN] Lua4z: the Lua programming language on z/OS, with
>>> batteries
>>>
>>>> -----Original Message-----
>>>> From: IBM Mainframe Discussion List [mailto:IBM-MAIN@LISTSERV.UA.EDU] On
>>>> Behalf Of David Crayford
>>>> Sent: Thursday, October 23, 2014 10:08 PM
>>>> To: IBM-MAIN@LISTSERV.UA.EDU
>>>> Subject: Re: [ANN] Lua4z: the Lua programming language on z/OS, with
>>>> batteries>
>>>>
>>>>
>>>
>>> <snip>
>>>
>>>> OK, let's try simple matrix multiplication which should test both array
>>>> access and math.
>>>>
>>>> /* REXX */
>>>> arg count
>>>> if count = "" then count = 1000000
>>>> start = sysvar("SYSCPU")
>>>> do i = 1 to count
>>>>   a.i = i * i
>>>> end
>>>> say 'CPU time = 'sysvar("SYSCPU") - start
>>>>
>>>> CPU time = 3.57
>>>>
>>>> local t = require("timer")()
>>>> local count = arg[1]  or 1000000
>>>> local a = {}
>>>> for i = 1, count do a[i]  = a[i] * i end
>>>> t:print_elapsed()
>>>>
>>>> elapsed time: 0.131965
>>>>
>>>>
>>>> That's a huge difference, two orders of magnitude.
>>>>
>>>
>>> <snip remainder>
>>>
>>> Maybe I'm just showing my ignorance of the Lua language syntax, but this
>>> statement: " a[i] = a[i] * i "
>>>
>>> Does not appear to be the equivalent to the REXX statement:
>>> " a.i = i * i "
>>>
>>> In fact, I would expect that the above Lua statement is actually
>>> multiplying i by an uninitialized variable "a[i]".  Assuming the above code
>>> executes without error, then due to the principle of least astonishment, I
>>> would imagine that this uninitialized value is assumed to be zero.
>>>
>>> If that IS what is happening, it will of course be MUCH faster to compute
>>> i * 0 than to compute i squared.
>>>
>>> Can someone with Lua syntax knowledge please enlighten me?
>>>
>>> Thanks,
>>> Bill Bass
>>> United HealthCare / Optum
>>>
>>>
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-- 
Mike A Schwab, Springfield IL USA
Where do Forest Rangers go to get away from it all?

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