> It doesn't do the same thing. Where .each runs the tests for every
> element in the collection and returns the collection, .cond() runs the
> tests once and returns anything you like.
Might I then suggest a simpler and more versatile method:
jQuery.fn.run = function (func, args)
{
this.length && func.apply(this, args||[]);
return this;
},
Used so:
jQuery('a').run(function(){
x === 1 ?
this.css({ color: 'blue' }):
x === 2 ?
this.css({ color: 'red' }):
test() ?
this.css({ color: val }):
this.css({ color: 'green' });
});
this `.run()` method has become part of my standard utility toolkit.
Highly efficient (only runs if the collection has length>0) and
provides the collection itself as this.
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups
"jQuery Development" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to
[email protected]
For more options, visit this group at
http://groups.google.com/group/jquery-dev?hl=en
-~----------~----~----~----~------~----~------~--~---
