Not sure what you're after, but based on your example, I think you could also just do: $([class^='class']).each(function() {....etc
That would find all elements with a class that starts with the word 'class' On Sep 23, 10:13 am, jeremyBass <[EMAIL PROTECTED]> wrote: > I think this would work... I'll try after loomin in to the "nth" > thing... thanks for the help, I'll get back soon... > jeremyBass > > On Sep 23, 2:56 am, BB <[EMAIL PROTECTED]> wrote: > > > Maybe you are looking for the $().filter() > > function:http://docs.jquery.com/Traversing/filter#fn > > > I don't know if this is working: > > > $("a[class^='myclass']").filter(function() { > > return /(myclass)[1-9]\d/.test(this.className);}).each(function() { > > > // do something here > > > }); > > > On 23 Sep., 05:13, jeremyBass <[EMAIL PROTECTED]> wrote: > > > > I want to make this work... > > > > $('.class' + [$[1-9][0-9]?] + '').each(function() {....etc > > > > mean that the class would be .class0 or .class99 etc. > > > > thanks for the help > > > jeremyBass > > > > note also tried: > > > $('[class=Round_gen^[1-9][0-9]?]').each(function() { > > > $('.Round_gen'+ [(/$[1-9][0-9]?/)] +'').each(function() { > > > $('.Round_gen'+ (/$[1-9][0-9]?/)]+'').each(function() { > > > along with many others...- Hide quoted text - > > > - Show quoted text -