There is no need for quotes as everything is already a string.
Jeremy, you need to understand what's going on:
$('[class^=Round_gen]').filter(function(){
// checks for any element where the 'class' attribute starts with
'Round_gen'
return /Round_gen[0-9]+/.test( $(this).attr('class') );
// 'test' is a method of the regular expression, that will test this
element's attribute 'class' against it, returning true or false. there
is no attribute called 'Round_gen'
}).each(function(){
var n = $(this).attr('class').match(/[0-9]+/);
// again, we are testing the CLASS attribute against the
regex, this will return the matched part (i.e the numbers in the
classname)
//in here you also want your code for each element, $(n) is not gonna
do anything as n is just a number, use $(this)
});
hope it's clearer now!
- ricardo
On Sep 23, 6:13 pm, tlphipps <[EMAIL PROTECTED]> wrote:
> Just need some quotes around the class name (I forgot to include some
> quotes in my example too)
>
> This should work:
> $("[class^='Round_gen']")
>
> On Sep 23, 4:04 pm, jeremyBass <[EMAIL PROTECTED]> wrote:
>
> > So tring to get this going I did
>
> > var n = '';
> > $('[class^=Round_gen]').filter(function(){
> > return /Round_gen[1-9][0-9]+/.test( $(this).attr('Round_gen')
> > );}).each(function(){
>
> > var n = $(this).attr('Round_gen').match(/[0-9]+/);
>
> > });
>
> > $('.Round_gen'+n+'').each(function() {...ect
>
> > and Got it picking up .Round_gen only ... not Round_gen9 or
> > Round_gen99
>
> > I think I'm close
> > thanks for the help...
> > jeremyBass
>
> > On Sep 23, 11:49 am, jeremyBass <[EMAIL PROTECTED]> wrote:
>
> > > So let say the class was named Round_gen9
>
> > > I'd replace
>
> > > $('.Round_gen9'').each(function() {....etc
>
> > > with
>
> > > $('[class^=Round_gen]').filter(function(){
> > > return /Round_gen[0-9]+/.Round_gen( $(this).attr('Round_gen')
> > > );}).each(function(){
>
> > > var n = $(this).attr('Round_gen').match(/[0-9]+/);
> > > // the number after 'class' for current element});
>
> > > $('n').each(function() {....etc
>
> > > nothing is showing up... so I don't think this is fully right (I mean
> > > what I wrote)
> > > ideas??
>
> > > Thanks for the help here...
> > > jeremyBass
>
> > > On Sep 23, 11:26 am, ricardobeat <[EMAIL PROTECTED]> wrote:
>
> > > > Using [class^=class] is your best bet, the other option is to loop
> > > > over all the possibilities and that is a no-go. Coupled with the
> > > > filter function this will give you all elements with classX where X is
> > > > a number:
>
> > > > $('[class^=class]').filter(function(){
> > > > return /class[0-9]+/.test( $(this).attr('class')
> > > > );}).each(function(){
>
> > > > var n = $(this).attr('class').match(/[0-9]+/); // the number
> > > > after 'class' for current element
>
> > > > });
>
> > > > hope this helps.
>
> > > > - ricardo
