That is sort of what I'm aimming at... I'm looking to find the last
part... they are all class0 class1 class99, but I want to do something
for each one.
basicly tring to find .class(someNUMBER)
hope that makes more sense...
thanks for the help
jeremyBass
On Sep 23, 9:38 am, tlphipps <[EMAIL PROTECTED]> wrote:
> Not sure what you're after, but based on your example, I think you
> could also just do:
> $([class^='class']).each(function() {....etc
>
> That would find all elements with a class that starts with the word
> 'class'
>
> On Sep 23, 10:13 am, jeremyBass <[EMAIL PROTECTED]> wrote:
>
>
>
> > I think this would work... I'll try after loomin in to the "nth"
> > thing... thanks for the help, I'll get back soon...
> > jeremyBass
>
> > On Sep 23, 2:56 am, BB <[EMAIL PROTECTED]> wrote:
>
> > > Maybe you are looking for the $().filter()
> > > function:http://docs.jquery.com/Traversing/filter#fn
>
> > > I don't know if this is working:
>
> > > $("a[class^='myclass']").filter(function() {
> > > return /(myclass)[1-9]\d/.test(this.className);}).each(function() {
>
> > > // do something here
>
> > > });
>
> > > On 23 Sep., 05:13, jeremyBass <[EMAIL PROTECTED]> wrote:
>
> > > > I want to make this work...
>
> > > > $('.class' + [$[1-9][0-9]?] + '').each(function() {....etc
>
> > > > mean that the class would be .class0 or .class99 etc.
>
> > > > thanks for the help
> > > > jeremyBass
>
> > > > note also tried:
> > > > $('[class=Round_gen^[1-9][0-9]?]').each(function() {
> > > > $('.Round_gen'+ [(/$[1-9][0-9]?/)] +'').each(function() {
> > > > $('.Round_gen'+ (/$[1-9][0-9]?/)]+'').each(function() {
> > > > along with many others...- Hide quoted text -
>
> > > - Show quoted text -- Hide quoted text -
>
> - Show quoted text -
