Hi Michael, I wrote this script some time ago, not really *heavily* tested yet but works nicely so far. Put the code in a movie script, then you can convert your propList into XML by doing
xmlString = propListToXML(myPropList) xml nodes will have a "ilk" attribute, which is used by the xmlToPropList function to set the correct types (string, list, symbol etc...) for xmlToPropList you have to parse your xml using the parser Xtra, make a propList with it and provide that as input to the xmlToPropList function. ----------------------------------------------- on propListToXML mList, mSub crlf = numToChar(13) & numToChar(10) tFile = "" if voidP(mSub) then tFile = openXMLnode(tFile, "xml") & crlf end if tCount = mList.count repeat with i = 1 to tCount tNode = mList.getPropAt(i) tIlk = ilk(mList[i]) if (tIlk = #propList) then tFile = openXMLnode(tFile, tNode) & crlf tFile = tFile & propListToXML(mList[i], 1) tFile = closeXMLnode(tFile, tNode) else ilkStr = string(tIlk) ilkStr = QUOTE & ilkStr.char[1..3] & QUOTE tString = string(tNode) && "ilk=" & ilkStr tFile = openXMLnode(tFile, tString) & mList[i] tFile = closeXMLnode(tFile, tNode) end if end repeat if voidP(mSub) then tFile = closeXMLnode(tFile, "xml") end if return tFile end -- input is meant to be a propList from the xml parser Xtra "makePropList" method on xmlToPropList mData tList = [:] tCount = mData.child.count repeat with i = 1 to tCount tNode = symbol(mData.child[i].name) if mData.child[i].child.count then val = xmlToPropList(mData.child[i]) else val = mData.child[i].charData tIlk = mData.child[i].attributes.ilk case tIlk of "str":nothing "int":val = integer(val) "flo":val = float(val) "sym":val = symbol(val) OTHERWISE: val = value(val) end case end if tList.addProp(tNode, val) end repeat return tList end on openXMLnode mFile, mNodeName -- crlf = numToChar(13) & numToChar(10) mFile = mFile & "<" & mNodeName & ">" -- & crlf return mFile end on closeXMLnode mFile, mNodeName crlf = numToChar(13) & numToChar(10) mFile = mFile & "</" & mNodeName & ">" & crlf return mFile end ------------------------------------------------- Hope this helps ! Selon Michael von Aichberger 2 <[EMAIL PROTECTED]>: > Hi List! > > The XML Parser Xtra converts XML-formatted text into a Lingo property list. > > Now, I need to do the opposite: I have a property list and would like to > convert that into an XML text. -- Mathieu Sénidre MatseMedia Développement multimédia online/offline tel 06 79 52 19 77 [To remove yourself from this list, or to change to digest mode, go to http://www.penworks.com/lingo-l.cgi To post messages to the list, email lingo-l@penworks.com (Problems, email [EMAIL PROTECTED]). Lingo-L is for learning and helping with programming Lingo. Thanks!]