On Thursday, 08/25/2011 at 09:29 EDT, "Edmund R. MacKenty"
<ed.macke...@rocketsoftware.com> wrote:
> With the NETMASK value you have there, the third component of your
NETWORK
> address must be 8 or higher, so 10241.8.0 is a valid network given that
> netmask. If the default route and NETWORK addresses are correct, then
your
> NETMASK should probably be 255.255.255.0. Try that.
I find this cheat-sheet I wrote up years ago very helpful at helping me
recognize when masks and subnet numbers aren't in alignment. It's easily
extended to include smaller masks.
There are plenty of online tools for IP address management, but this chart
had what *I* wanted on it. :-)
Mask Last
size Octet Binary subnetwork # hosts
/25 128 1000 0000 2: 0 128 126
/26 192 1100 0000 4: 0 64 128 192 62
/27 224 1110 0000 8: 0 32 64 96 128 160 192 224 30
/28 240 1111 0000 16: 0 16 32 48 64 80 96 112 14
128 144 160 176 192 208 224 240
/29 248 1111 1000 32: 0 8 16 24 32 40 48 56 6
64 72 80 88 96 104 112 120
128 136 144 152 160 168 176 184
192 200 208 216 224 232 240 248
/30 252 1111 1100 64: 0 4 8 12 16 20 24 28 2
32 36 40 44 48 52 56 60
64 68 72 76 80 84 88 92
96 100 104 108 112 116 120 124
128 132 136 140 144 148 152 156
160 164 168 172 176 180 184 188
192 196 200 204 208 212 216 220
224 228 232 236 240 244 248 252
Alan Altmark
Senior Managing z/VM and Linux Consultant
IBM System Lab Services and Training
ibm.com/systems/services/labservices
office: 607.429.3323
mobile; 607.321.7556
alan_altm...@us.ibm.com
IBM Endicott
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