On Tue, Mar 27, 2018 at 12:34:53PM +0100, Russell King - ARM Linux wrote:
> On Tue, Mar 27, 2018 at 10:04:10AM +0100, Russell King - ARM Linux wrote:
> > On Fri, Mar 23, 2018 at 11:14:53AM -0700, Tony Lindgren wrote:
> > > Hi,
> > >
> > > Looks like commit 5638790dadae ("zboot: fix stack protector in
> > > compressed boot phase") breaks booting on arm.
> > >
> > > This is all I get from the bootloader on omap3:
> > >
> > > Starting kernel ...
> > >
> > > data abort
> > > pc : [<810002d0>] lr : [<100110a8>]
> > > reloc pc : [<9d6002d0>] lr : [<2c6110a8>]
> > > sp : 81467c18 ip : 81466bf0 fp : 81466bf0
> > > r10: 80fc2c40 r9 : 81000258 r8 : 86fec000
> > > r7 : ffffffff r6 : 81466bf8 r5 : 00000000 r4 : 80008000
> > > r3 : 81466c14 r2 : 81466c18 r1 : 000a0dff r0 : 00466bf8
> > > Flags: nZCv IRQs off FIQs off Mode SVC_32
> > > Resetting CPU ...
> > >
> > > resetting ...
> >
> > The reason for this is the following code that was introduced by the
> > referenced patch:
> >
> > + ldr r0, =__stack_chk_guard
> > + ldr r1, =0x000a0dff
> > + str r1, [r0]
> >
> > This uses the absolute address of __stack_chk_guard in the decompressor,
> > which is a self-relocatable image. As with all constructs like the
> > above, this absolute address doesn't get fixed up, and so it ends up
> > pointing at invalid memory (in this case 0x466bf8) vs RAM at 0x80000000,
> > and the decompressor looks to be around 0x81000000.
> >
> > Such constructs can not be used in the decompressor for exactly this
> > reason - they need to use PC-relative addressing instead just like
> > everything else does in head.S.
>
> Is there any reason we can't do this in misc.c:
>
> const unsigned int __stack_chk_guard = 0x000a0dff;
>
> ? That would save having runtime code to set that value up, and after
> all, it is constant. Arguments about it potentially ending up at a
> fixed offset into the image need not be said - that's already the case
> with placing it in the early assembly code, and as has been established,
> it needs to be initialised prior to any C code being called.
I've asked this multiple times in this thread and as far as I know
nobody has answered.
Rich
