----- Original Message ----- 
  From: oso954 
  To: [email protected] 
  Sent: Friday, October 21, 2005 17:05
  Subject: [microhydro] Re: auto alternator output


    "  Hello Radu:

  First thing, when you provide a link, please do not enclose it in 
  parentheses ( ). It makes the link inoperable for those people who 
  have browsers that handle the links.

  Secondly, I think we need to back this conversation up and start at 
  what should have been the beginning.  You cannot really discuss a 
  mini hydro installation intelligently, unless you give some idea of 
  the loads that the system is expected to carry, hopefully the timing 
  of those loads, and other details of how the system is operate. "




       Great point, Oso !   

  I am sure that you right, because there is  absolutely the same principle
  like in electrical circuitry: the COMPATIBILITY  of source of energy ( flow 
of 
  mass)  and  mechanical load (turbine, water wheel, ram pump, etc).
  By analogy we may expect that criterion  of COMPATIBILITY is:

                                  Rl= Rl
  where:

   Rf - analogy "hydro resistance" of flow
   Rl - analogy "hydro resistance" of load

  The next step is how to define these values  ( Rf,  Rl )
  I have determined just  Rl right now as:

   Rf = h/dxV  x l/S         (1)

  where:

   h - head [m],
  d - density of flow  [ kg/mxmxm],
  V - velocity of flow [m/sec],
  l  - length of penstock (pipe) [m],
  S - square of section of penstock (pipe) [mxm]

  You can see that the structure of (1) is 
  absolutely like R(Ohm) for electricity,
  where:
                              r = h/dxV

  could be interpreted like

  r - "specific hydro resistance" of flow

  I think it would be interested to apply   (1)  for
  practical estimation.  Everyone can do it.

     
                                                            Alex
   
   





[Non-text portions of this message have been removed]





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