At 10:25 AM +0100 11/7/00, [EMAIL PROTECTED] wrote:
>On Tue, 7 Nov 2000, Ron Rademaker wrote:
>
>Hi,
>
>> You would think so, however every doc I read (including the one you
>> pointed out to me) told me that perl gives me a warning:
>>
>> Variable $foo will not stay shared at ....
>>
>> I do use -w so I should get that warning, but I don't. The variable stays
>> defined, but it doesn't have the value of the old variable, it just passes
>> the defined($foo) test but the value has changed to an empty array (from a
>> full array).
>
>-w has no effect, read the guide again and use PerlWarn On :-)
Please explain, the guide appears to recommend -w as a useful
diagnostic technique (and the "Command Line Switches (-w, -T,
etc)" section says -w works).
>
>Bye,
>remco
>
>/----------------------------------------------------------------------\
>| Remco Schaar |
>| e-mail: [EMAIL PROTECTED] |
>\----------------------------------------------------------------------/
>
> South Park meets Linux:
> - "Oh my God, they killed init!"
> - "You bastards!"
