Ok. I think I am close to getting this. Here is what I have.
MYSQL="/usr/local/mysql/bin/mysql --user=$username --password=$password
--host=$server cetechnology"
RESULT=$(echo "select count(*) from hardware_assets where
ethernet_address='$ethernet_address' " | $MYSQL)
if [ "$RESULT" = "0" ] ; then
echo "INSERT INTO hardware_assets (ethernet_address) VALUES
('$ethernet_address');" | $MYSQL
else
echo "UPDATE hardware_assets SET operating_system='10.3.3';" | $MYSQL
fi
echo $RESULT
When I run this, it always does an update, and updates all records, not just
the ones that are matching $ethernet_address. I added the 'echo $RESULT' to
see what it was returning. It comes back with 'count(*) 1'. I change the if
statement to read 'if["$RESULT" = "count(*) 0" and the value for
$ethernet_address to a number that I do not have in the database. It does
not add the new ethernet address, and updates all of the records.
So that tells me that there is something wrong the value of $RESULT and the
comparison in the if statement. Further, if I change the value of $RESULT to
'12345' and change the if line to
if [ "$RESULT" = "12345" ] ; then
It adds a record to the database. So there is something wrong with what is
returned. Neither "0" or "count(*) 0" seem to work. So, does anyone have an
idea as to what I need to put in for the comparison?
Mike
> From: gerald_clark <[EMAIL PROTECTED]>
> Date: Mon, 09 Feb 2004 14:28:27 -0600
> To: Mike Tuller <[EMAIL PROTECTED]>
> Cc: MySql List <[EMAIL PROTECTED]>
> Subject: Re: There has to be a way to do this
>
> This is NOT a script that can run under mysql.
> It is a bash script that calls mysql.
>
> MYSQL="/usr/local/mysql/bin/mysql --user=$username --password=$password
> --host=$server cetechnology"
>
> RESULT=`echo "select count(*) from hardware_assets where
> ethernet_address='$ethernet_address'" | $MYSQL
> if [ "$RESULT" = "0" ] ; then
> echo "INSERT INTO hardware_assets (ethernet_address) VALUES
> ($ethernet_address);" |$MYSQL
> else
> echo "UPDATE hardware_assets SET operating_system='10.3.3';" | $MYSQL
> fi
>
>
> Mike Tuller wrote:
>
>> I changed my script to this:
>>
>> /usr/local/mysql/bin/mysql --user=$username --password=$password
>> --host=$server
>>
>> RESULT=`echo "select count(*) from hardware_assets where
>> ethernet_address='$ethernet_address'" | cetechnology'
>> if [ "$RESULT" = "0" ] ; then
>> echo "INSERT INTO hardware_assets (ethernet_address) VALUES
>> ($ethernet_address);"
>> else
>> echo "UPDATE hardware_assets SET operating_system='10.3.3';"
>> fi
>>
>> Where cetechnology is the database. All the variables are set.
>>
>> When I run this, it starts the mysql client application, with the mysql>
>> prompt. Nothing is inserted or updated in the database though.
>>
>> This is the same problem I had when I tried to do it this way, but I am not
>> knowledgeable in shell scripting yet to know what I am doing wrong.
>>
>>
>>
>>
>>
>>
>>> From: gerald_clark <[EMAIL PROTECTED]>
>>> Date: Mon, 09 Feb 2004 11:11:24 -0600
>>> To: Mike Tuller <[EMAIL PROTECTED]>
>>> Cc: MySql List <[EMAIL PROTECTED]>
>>> Subject: Re: There has to be a way to do this
>>>
>>> IF works on the selections not on the query.
>>> Select IF(lastname='clark','Correct',''Incorrect'), firstname from
>>> namefile;
>>>
>>> You need to do the checking in your script.
>>> For example in bash:
>>> RESULT=`echo "select count(*) from manefile where lastname='clark'" |
>>> mysql database`
>>> if [ "$RESULT" = "0" ] ; then
>>> echo "insert into namefile .......
>>> else
>>> echo "update namefile ......
>>> fi
>>>
>>>
>>> Mike Tuller wrote:
>>>
>>>
>>>
>>>> I have posted this question a few times, and have not seen the answer that
>>>> I
>>>> need.
>>>>
>>>> I have a shell script, that gathers information from systems, and I want
>>>> that info to be entered into a database. I want it to check first to see if
>>>> the data is already entered, and if not, add it. If it has already been
>>>> entered, then update the record.
>>>>
>>>> I would think that some type of if/else statement would work, but I can't
>>>> get the IF statement http://www.mysql.com/doc/en/IF_Statement.html to work
>>>> correctly in MySql.
>>>>
>>>> Here is what I have:
>>>>
>>>> "IF SELECT * FROM hardware_assets WHERE
>>>> ethernet_address='$ethernet_address'
>>>> IS NULL\
>>>> THEN INSERT into hardware_assets (ethernet_address) VALUES
>>>> ($ethernet_address)\
>>>> ELSE\
>>>> UPDATE hardware_assets SET operating_system='10.3.3'\
>>>> END IF;"
>>>>
>>>> I get back that I have an error in my SQL syntax. $ethernet_address is set,
>>>> so that is not my problem.
>>>>
>>>> Does anyone know a way to go about this in SQL, or in a shell script? I
>>>> don't want to do it in Perl or PHP.
>>>>
>>>>
>>>> Thanks,
>>>> Mike
>>>>
>>>>
>>>>
>>>>
>>>>
>>>>
>>>
>>> --
>>> MySQL General Mailing List
>>> For list archives: http://lists.mysql.com/mysql
>>> To unsubscribe:
>>> http://lists.mysql.com/[EMAIL PROTECTED]
>>>
>>>
>>>
>>
>>
>>
>>
>
>
--
MySQL General Mailing List
For list archives: http://lists.mysql.com/mysql
To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
