Mike Tuller wrote:
Ok. I think I am close to getting this. Here is what I have.RESULT=`echo "se;ect count(*) from hardware_assets where ethernet_address='$ethernet_address' " | $MYSQL`
MYSQL="/usr/local/mysql/bin/mysql --user=$username --password=$password --host=$server cetechnology"
RESULT=$(echo "select count(*) from hardware_assets where
the first and last quotes are actually back-ticks ( to the left of the `1' Key )
ethernet_address='$ethernet_address' " | $MYSQL) if [ "$RESULT" = "0" ] ; then echo "INSERT INTO hardware_assets (ethernet_address) VALUES ('$ethernet_address');" | $MYSQL else echo "UPDATE hardware_assets SET operating_system='10.3.3';" | $MYSQL fi
echo $RESULT
When I run this, it always does an update, and updates all records, not just the ones that are matching $ethernet_address. I added the 'echo $RESULT' to see what it was returning. It comes back with 'count(*) 1'. I change the if statement to read 'if["$RESULT" = "count(*) 0" and the value for $ethernet_address to a number that I do not have in the database. It does not add the new ethernet address, and updates all of the records.
So that tells me that there is something wrong the value of $RESULT and the comparison in the if statement. Further, if I change the value of $RESULT to '12345' and change the if line to if [ "$RESULT" = "12345" ] ; then It adds a record to the database. So there is something wrong with what is returned. Neither "0" or "count(*) 0" seem to work. So, does anyone have an idea as to what I need to put in for the comparison?
Mike
From: gerald_clark <[EMAIL PROTECTED]> Date: Mon, 09 Feb 2004 14:28:27 -0600 To: Mike Tuller <[EMAIL PROTECTED]> Cc: MySql List <[EMAIL PROTECTED]> Subject: Re: There has to be a way to do this
This is NOT a script that can run under mysql. It is a bash script that calls mysql.
MYSQL="/usr/local/mysql/bin/mysql --user=$username --password=$password --host=$server cetechnology"
RESULT=`echo "select count(*) from hardware_assets where ethernet_address='$ethernet_address'" | $MYSQL if [ "$RESULT" = "0" ] ; then echo "INSERT INTO hardware_assets (ethernet_address) VALUES ($ethernet_address);" |$MYSQL else echo "UPDATE hardware_assets SET operating_system='10.3.3';" | $MYSQL fi
Mike Tuller wrote:
I changed my script to this:
/usr/local/mysql/bin/mysql --user=$username --password=$password
--host=$server
RESULT=`echo "select count(*) from hardware_assets where ethernet_address='$ethernet_address'" | cetechnology' if [ "$RESULT" = "0" ] ; then echo "INSERT INTO hardware_assets (ethernet_address) VALUES ($ethernet_address);" else echo "UPDATE hardware_assets SET operating_system='10.3.3';" fi
Where cetechnology is the database. All the variables are set.
When I run this, it starts the mysql client application, with the mysql> prompt. Nothing is inserted or updated in the database though.
This is the same problem I had when I tried to do it this way, but I am not knowledgeable in shell scripting yet to know what I am doing wrong.
From: gerald_clark <[EMAIL PROTECTED]> Date: Mon, 09 Feb 2004 11:11:24 -0600 To: Mike Tuller <[EMAIL PROTECTED]> Cc: MySql List <[EMAIL PROTECTED]> Subject: Re: There has to be a way to do this
IF works on the selections not on the query. Select IF(lastname='clark','Correct',''Incorrect'), firstname from namefile;
You need to do the checking in your script. For example in bash: RESULT=`echo "select count(*) from manefile where lastname='clark'" | mysql database` if [ "$RESULT" = "0" ] ; then echo "insert into namefile ....... else echo "update namefile ...... fi
Mike Tuller wrote:
I have posted this question a few times, and have not seen the answer that I need.
I have a shell script, that gathers information from systems, and I want that info to be entered into a database. I want it to check first to see if the data is already entered, and if not, add it. If it has already been entered, then update the record.
I would think that some type of if/else statement would work, but I can't get the IF statement http://www.mysql.com/doc/en/IF_Statement.html to work correctly in MySql.
Here is what I have:
"IF SELECT * FROM hardware_assets WHERE ethernet_address='$ethernet_address' IS NULL\ THEN INSERT into hardware_assets (ethernet_address) VALUES ($ethernet_address)\ ELSE\ UPDATE hardware_assets SET operating_system='10.3.3'\ END IF;"
I get back that I have an error in my SQL syntax. $ethernet_address is set, so that is not my problem.
Does anyone know a way to go about this in SQL, or in a shell script? I don't want to do it in Perl or PHP.
Thanks, Mike
-- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]
-- MySQL General Mailing List For list archives: http://lists.mysql.com/mysql To unsubscribe: http://lists.mysql.com/[EMAIL PROTECTED]