Hi Ingo,
On Mon, Mar 08, 2021 at 09:49:06AM +0100, Ingo Schmid wrote:
> ...
> is it not doing ci() + $x (expected behaviour) rather than ci( +$x) ?
No. For example:
$ pdl2
...
pdl> $x=1+0*ci # initialize a complex variable with a real value
pdl> p $x
1+0i
pdl> p ci()+$x # this works as expected
1+1i
pdl> p ci+$x # this doesn't
pdl> p $x # and the value of $x has been changed
0+1i
Curiously,
pdl> p ci-$x
doesn't print anything either, but it doesn't change $x (I guess -$x
is assigned to a temporary variable and that is what gets modified by
ci; in ci+$x a temporary variable is not necessary so $x itself gets
modified).
Regards,
Luis
--
o
W. Luis Mochán, | tel:(52)(777)329-1734 /<(*)
Instituto de Ciencias Físicas, UNAM | fax:(52)(777)317-5388 `>/ /\
Av. Universidad s/n CP 62210 | (*)/\/ \
Cuernavaca, Morelos, México | [email protected] /\_/\__/
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