At 08:10 PM 05-14-2001 +0100, Graham Barr wrote:
>On Mon, May 14, 2001 at 01:56:01PM -0500, Me wrote:
> > > Hm, OK. What does this access and using what method ?
> > >
> > > $foo = '1.2';
> > > @bar[$foo];
> >
> > This is an argument against conflating @ and %.
>
>No it is not.
>
> > It has nothing to do with using [] instead of {}.
>
>Yes it does. I was asking if the above is equivalent to
>
> $bar[$foo] or $bar{$foo} in todays perl.
What is the meaning of the following four expressions in Perl6?
@bar[$foo]; # A
%bar{$foo}; # B
@bar{$foo}; # C
%bar[$foo]; # D
You seem to be advocating A and B, "Me" is advocating A and D.
Why is one set better than the other?
Later,
Buddha
- RE: what I meant about hungarian notation <C. Garrett Goebel>
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Larry Wall
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Damian Conway
- Re: what I meant about hungarian notation Michael G Schwern
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Buddha Buck
- Re: what I meant about hungarian notation Damian Conway
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation John Porter
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation John Porter
- Re: what I meant about hungarian notation Graham Barr
- Re: what I meant about hungarian notation Me
- Re: what I meant about hungarian notation David L. Nicol
- Re: what I meant about hungarian notation Graham Barr
