--- Jonathan Scott Duff <[EMAIL PROTECTED]> wrote: > On Wed, Oct 30, 2002 at 09:13:02AM -0800, Austin Hastings wrote: > > --- Jonathan Scott Duff <[EMAIL PROTECTED]> wrote: > > > Maybe we've gone over this before but, if so, I don't remember > ... > > > > > > On Tue, Oct 29, 2002 at 05:16:48PM -0800, Michael Lazzaro wrote: > > > > hyperoperators: > > > > > > > > [op] - as prefix to any unary/binary operator, "vectorizes" > the > > > > > > > operator > > > > > > > . - method call on current topic > > > > > > What would [.]method() mean? > > > > @a = @b[.]method(); # Sets each @a[x] to @b[x].method() > > No, no. I'm talking about the unary . prefix > > method blah { > .foo() > [.]foo() # What does this mean? > }
Vector of invocations of the foo methods of the current topic. Presumably you'd have an array in topic, or you'd use it in an array context. for @lol -> @onelist { @a = [.]foo(); } =Austin __________________________________________________ Do you Yahoo!? HotJobs - Search new jobs daily now http://hotjobs.yahoo.com/