Maybe you're asking something else, like what is the "normal" lens for 6x9 film. I think it would be the same length as a diagonal from one corner of your film to the other. So, to calculate that you would take the square root of (6x6 + 9x9) which is approximately 11cm or 110mm. I think thats right. ----- Original Message ----- From: luciana napchan To: pinhole-discussion@p at ??????? Sent: Friday, October 26, 2001 9:52 AM Subject: Re: [pinhole-discussion] Micro or macro photo with pinhole photo
Thank you for your response But I did not want a wide angle image, so for instance, if I want to make images of fruits, with a 6X9 120mm film, is my image going to be distorces ? How can I have a normal image for a 120mm film ? I do have a zero 6x9 camera and thinking to built a 4X5 one Thank you so much Luciana >From: George L Smyth >Reply-To: pinhole-discussion@p at ??????? >To: pinhole-discussion@p at ??????? >Subject: Re: [pinhole-discussion] Micro or macro photo with pinhole photo >Date: Fri, 26 Oct 2001 09:36:25 -0700 (PDT) > > >--- luciana napchan wrote: > > ------------------------------------------------------------------------------ > > I would like to know which camera should I use to make macro or >micro photography with pinhole ? > >It doesn't matter - just place your subject close to the pinhole. > >Cheers - > >george > >===== >Handmade Photographic Images >http://members.home.net/hmpi/ > >__________________________________________________ >Do You Yahoo!? >Make a great connection at Yahoo! Personals. >http://personals.yahoo.com > >_______________________________________________ >Pinhole-Discussion mailing list >Pinhole-Discussion@p at ??????? >unsubscribe or change your account at >http://www.???????/discussion/ ------------------------------------------------------------------------------ Get your FREE download of MSN Explorer at http://explorer.msn.com _______________________________________________ Pinhole-Discussion mailing list Pinhole-Discussion@p at ??????? unsubscribe or change your account at http://www.???????/discussion/
