On 8/27/2010 2:17 AM, Ralph Seichter wrote:
I wonder if I was being too imprecise? I can of course provide "postconf -n"
(and/or "dovecot -n") output if it should be required to answer my question.
-------- Original Message --------
Subject: How to drop the recipient address hostname when delivering mail via
LMTP?
Date: Wed, 25 Aug 2010 21:08:42 +0200
From: Ralph Seichter<postfix...@seichter.de>
To: postfix-users@postfix.org
There is a thread in the Dovecot mailing list discussing this subject,
but I think it best to ask here aswell:
My Dovecot 2.0 configuration contains these lines
auth_username_format = %Ln
service lmtp {
unix_listener /var/spool/postfix/private/dovecot-lmtp {
user = postfix
group = postfix
mode = 0660
}
}
and I have included the lines
myhostname = server.domain.tld
mydestination = $myhostname localhost.$mydomain localhost
mailbox_transport = lmtp:unix:private/dovecot-lmtp
in my main.cf. When Postfix is asked to deliver mail to
u...@server.domain.tld
it does so using Dovecot's LMTP socket. What bothers me about this
configuration is "auth_username_format = %Ln" in my Dovecot config.
The parameter affects all user lookups, which means that one cannot
distinguish between u...@domaina and u...@domainb during IMAP login.
I wonder how I can setup a transport which drops the @server.domain.tld
suffix when Postfix delivers mail via LMTP?
-Ralph
I think the problem is better solved in the delivery agent.
If you're using the postfix LMTP client, this might work:
http://www.postfix.org/postconf.5.html#lmtp_generic_maps
/^(.*)@server\.example\.com$/ $1
This will also mangle To: headers.
If you're using a postfix pipe(8) based transport, you could
use the ${user} or ${mailbox} macros to eliminate the domain
name, but these options aren't available for lmtp or smtp.
http://www.postfix.org/pipe.8.html
-- Noel Jones
