On Tue, Dec 6, 2011 at 11:32 AM, Linda Alvord <lindaalv...@verizon.net> wrote: > For number 2 each time you toss the dice, you must get a total for all the > 500 dice. Next you toss the full bucket of dice 199 more times. Make a > frequency distribution of the 200 results.
If I implement this description of number 2 I get almost 200 different sums of the 200 throws of 500 dice, i.e. almost all of the sums have a frequency of 1 (the odd one has 2 or 3). platonic=: 4 6 8 12 20 sumtoss=: [: +/ ?@$ fd=: [: /:~ ({. , #)/.~ fd 500 200 sumtoss platonic ---------------------------------------------------------------------- For information about J forums see http://www.jsoftware.com/forums.htm