That really was some frequency distribution!
In my thinking the sum of any one toss would range from 5 to 50.
Here's how the story started in my imagination:
7#"1 ,.4 6 8 12 20
4 4 4 4 4 4 4
6 6 6 6 6 6 6
8 8 8 8 8 8 8
12 12 12 12 12 12 12
20 20 20 20 20 20 20
How about if you word an interesting problem to make lots of tosses of these
5 dice and make a sensible frequency distribution using simple J ?
I've been wondering why no one solved it in a day or two.
Too many things interested me this week. Plot is now working nicely. The
Turkey Challenge has been an endless challenge. An excursion in the
imaginary realm which I have ignored for more than 20 years didn't help.
I'd like to ponder your frequency distribution and finalize a really concise
summary for the turkeys.
Thanks in advance.
Linda
-----Original Message-----
From: programming-boun...@jsoftware.com
[mailto:programming-boun...@jsoftware.com] On Behalf Of Ric Sherlock
Sent: Wednesday, December 07, 2011 4:20 AM
To: Programming forum
Subject: Re: [Jprogramming] Many Turkey Rolls - No embargo
On Wed, Dec 7, 2011 at 10:16 PM, Ric Sherlock <tikk...@gmail.com> wrote:
> On Tue, Dec 6, 2011 at 11:32 AM, Linda Alvord <lindaalv...@verizon.net>
wrote:
>> For number 2 each time you toss the dice, you must get a total for all
the
>> 500 dice. Next you toss the full bucket of dice 199 more times. Make a
>> frequency distribution of the 200 results.
>
> If I implement this description of number 2 I get almost 200 different
> sums of the 200 throws of 500 dice, i.e. almost all of the sums have a
> frequency of 1 (the odd one has 2 or 3).
>
> platonic=: 4 6 8 12 20
> sumtoss=: [: +/ ?@$
> fd=: [: /:~ ({. , #)/.~
> fd 500 200 sumtoss platonic
Sorry sumtoss should be:
sumtoss=: [: +/ 1 + ?@$
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