On 2011-12-26, Charles Elliott <elliott...@verizon.net> wrote: > > > > >> -----Original Message----- > >> From: questions-bounces+elliott.ch=verizon....@lists.ntp.org > >> [mailto:questions-bounces+elliott.ch=verizon....@lists.ntp.org] On > >> Behalf Of unruh > >> Sent: Sunday, December 25, 2011 4:46 PM > >> To: questions@lists.ntp.org > >> Subject: Re: [ntp:questions] Windows and Wi-Fi - starts well, frequency > >> steps? > >> > >> On 2011-12-25, Charles Elliott < <mailto:elliott...@verizon.net> > elliott...@verizon.net> wrote: > >> ntp assumes that the outgoing and incoming trips are the same time. If >> not, you get an offset. Thus if the return trip takes 10 min and the >> outgoing 1ms, ntp is going to say that the remote clock is five minutes >> further behind than it is. On a wireless I could easily imagine that >> the >> trip times are not the same, and that one way of the other is >> preferentially got a higher jitter than the other. > > That's true. But that the offset becomes more negative as the delay > increases implies that the response trip always takes longer than the > request trip. Isn't that somewhat unlikely? Why would not the request and > response times be equal on average? That is, on average why don't the path > asymmetries cancel each other out?
Why is it unlikely? And even if it is, why could it not be happening to you? the two paths ARE assymetric--in one case it is the modem that is receiving the wireless signal, in the other your machine. If your modem's wireelss is weak or noisier than your machine's it could case an assymetry. But this is irrelevant. Your measurements indictate that this is what is happening. _______________________________________________ questions mailing list questions@lists.ntp.org http://lists.ntp.org/listinfo/questions
