cloud-fan commented on code in PR #36968:
URL: https://github.com/apache/spark/pull/36968#discussion_r905773687
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sql/core/src/main/scala/org/apache/spark/sql/internal/CatalogImpl.scala:
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@@ -243,7 +243,29 @@ class CatalogImpl(sparkSession: SparkSession) extends
Catalog {
* `Database` can be found.
*/
override def getDatabase(dbName: String): Database = {
- makeDatabase(dbName)
+ // `dbName` could be either a single database name (behavior in Spark 3.3
and prior) or a
+ // qualified namespace with catalog name. To maintain backwards
compatibility, we first assume
+ // it's a single database name and return the database from sessionCatalog
if it exists.
+ // Otherwise we try 3-part name parsing and locate the database. If the
parased identifier
+ // contains both catalog name and database name, we then search the
database in the catalog.
+ if (sessionCatalog.databaseExists(dbName) ||
sessionCatalog.isGlobalTempViewDB(dbName)) {
+ makeDatabase(dbName)
+ } else {
+ val ident =
sparkSession.sessionState.sqlParser.parseMultipartIdentifier(dbName)
+ val plan = UnresolvedNamespace(ident)
+ val resolved = sparkSession.sessionState.executePlan(plan).analyzed
+ val db = ident.tail
+ val metadata = resolved match {
+ case ResolvedNamespace(catalog: SupportsNamespaces, _) =>
+ catalog.loadNamespaceMetadata(db.toArray)
+ // TODO what to do if it doesn't support namespaces
+ case _ => throw new RuntimeException(s"unexpected catalog resolved:
$resolved")
Review Comment:
Let's follow `databaseExists`: if the catalog doesn't support namespace, we
assume it's an implicit namespace, which exists but has no metadata.
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