Hello! I'm developing a classical Blog like app, and I'm having some kind of issues about posts' tags, because I've correctly installed acts_as_taggable and acts_as_taggable_on_steroids gems but none of them work, for a controller's mismatch error (due to a Post's tags:string attribute I guess), but still, this is not important.
What I want to do is a Blogspot's like schema, so basically there is the http://website/search/label/***TAG_NAME*** url, which contains all the posts done with this specific tag. Well then, I've split the tags and each tag redirect to the correct url, which contains all the posts made with the related tag, BUT I just manually created the routes and templates. The problem is : how could I tell to the controller to create an action, or a method with the same name of those tags inside the Search controller? I was thinking to a Proc, but I have no clue about how to structure it. Could you help me? And also, when I create a new Post, if I write in tags' text_field something like "wood,fire", Rails will save the string as a single tag, but what I evidently want is to .split(',') this string. Yet, I'm not able to find the place in between f.submit and the PostsController, where the tags would be sent to the Controller already split up. Cos, if I put the split after the : if @post.save @post.tags.split(',') ...in the console I get: >>Post.last => [ #etc etc. tags : "wood,fire"] and it isn't split. Otherwise, if I put the .split(',') method somewhere into the _form I get errors. So, basically I'm looking for the "place" in the middle between the submit action and the Controller's final check. Any idea??? :) -- Posted via http://www.ruby-forum.com/. -- You received this message because you are subscribed to the Google Groups "Ruby on Rails: Talk" group. To post to this group, send email to rubyonrails-talk@googlegroups.com. To unsubscribe from this group, send email to rubyonrails-talk+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/rubyonrails-talk?hl=en.
